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yarga [219]
3 years ago
7

No matter where you are on Earth, the center of the Earth is always _______.

Chemistry
2 answers:
FinnZ [79.3K]3 years ago
4 0

Answer:

D) straight down

Hope this helps!

Vesna [10]3 years ago
4 0

Answer: Straight down

Explanation:

Hope this helps!

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Come up with a three-step plan for your household to reduce its effect on water pollution. Your plan should include a way to edu
Marina86 [1]

Answer:

1 tell your family difrent ways to safe water

2 dont leave the water running when you brush your teeth

3 dont dump cups of water out for no reason

Explanation:

3 0
3 years ago
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Diffrence btwn a period and a group
Tpy6a [65]
Rows of elements are called periods. The period number<span> of an element signifies the highest unexcited energy level for an electron in that element.

</span>Columns of elements help define element groups<span>. </span>Elements within a group share<span> several common properties. Groups are elements have the same outer electron arrangement.</span>
8 0
3 years ago
Which of the following terms describes an accumulation of rocky, sandy, or clayey material deposited at the end of a glacier?
OLEGan [10]

Answer:

Option (D)

Explanation:

<u>Eskers are the long ridges that are comprised of rocks, sands and clay particles and are deposited towards the end of the glaciers</u>. These are fluvioglacial depositional features. These particles are exposed after the glaciers recede. These ridges are formed parallel to the earlier flow direction of ice. The size of eskers is generally smaller as it carries smaller particles such as rocks, sands, and gravels, in comparison to the different type of moraines. It is because the flow velocity decreases as the glaciers melt. So, these eskers are formed at the end of the glaciers.

Thus, the correct answer is option (D).

3 0
3 years ago
Given the following information:Br2 bond energy = 193 kJ/mol F2 bond energy = 154 kJ/mol 1/2Br2(g) + 3/2F2(g) -&gt; BrF3(g) = –3
arlik [135]

Answer:

C) 712 KJ/mol

Explanation:

  • ΔH°r = Σ Eb broken - Σ Eb formed
  • 1/2Br2(g) + 3/2F2(g) → BrF3(g)

∴ ΔH°r = - 384 KJ/mol

∴ Br2 Eb = 193 KJ/mol

∴ F2 Eb = 154 KJ/mol

⇒ Σ Eb broken = (1/2)(Br-Br) + (3/2)(F-F)

⇒ Σ Eb broken =  (1/2)(193 KJ/mol) + (3/2)(154 KJ/mol) = 327.5 KJ/mol

∴ Eb formed: Br-F

⇒ Σ Eb formed (Br-F) = Σ Eb broken - ΔH°r

⇒ Eb (Br-F) = 327.5 KJ/mol - ( - 384 KJ/mol )

⇒ Eb Br-F = 327.5 KJ/mol + 384 KJ/mol = 711.5 KJ/mol ≅ 712 KJ/mol

8 0
3 years ago
I need help with this plz ???
saw5 [17]

Answer:

what is that what grade is that is so confusing

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