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Alekssandra [29.7K]
2 years ago
5

How many moles are in 3.0x10^24 molecules of water​

Chemistry
2 answers:
Daniel [21]2 years ago
5 0
<h3>I HOPE MY ANSWER HELPS YOU;))</h3>

SpyIntel [72]2 years ago
5 0

Answer:

3.52 x 10^24 molecules x `1mol/6.02 x 10^23 molecules = 5.85 moles of H2O.

Explanation:

You might be interested in
What is the amount of moles in 67 g of C​
Tju [1.3M]

Answer:The molar mass of atoms of an element is given by the standard relative atomic mass of the element multiplied by the molar mass constant, 1 × 10−3 kg/mol = 1 g/mol.

Explanation:

3 0
2 years ago
A 2.684-g sample of zinc oxide was reduced by hydrogen gas, resulting in 2. 156 g of pure zinc metal. Determine the empirical fo
Afina-wow [57]

The empirical formula of the initial zinc oxide is ZnO.

<h3>What is Empirical Formula?</h3>

The empirical formula of a compound represents the ratios of elements in a compound but not the actual numbers or arrangement of the atoms.

It is the lowest whole number ratio of the element in the compound.

<h3>How to find out the empirical formula?</h3>
  • Find out the given masses and molar masses of the elements

The molar mass of Zn = 65 gmol⁻¹

Given the mass of Zn = 2.156 g

The molar mass of Oxygen = 16 gmol⁻¹

The mass of Oxygen = Mass of a sample of zinc oxide - the mass of zinc metal

                                   = (2.684 - 2.156) g

                                   = 0.528 g

  • Find the number of moles of the elements in the compound

The number of moles is given by

n = \frac{m}{M}

where m = given mass and

M = Molar mass

Number of moles of Zinc = \frac{2.156}{65} = 0.033 moles

Number of moles of Oxygen =\frac{0.528}{16} = 0.033 moles

  • Find the simplest ratios of the elements in the compound. To find the ratios simply divide the number of moles by the lowest number of moles obtained.

Here, the number of moles is the same for both elements. Hence, the simplest ratio for Zn:O is 1:1.

Therefore, the empirical formula of zinc oxide is ZnO.

Learn more about the empirical formula:

brainly.com/question/1603500

#SPJ4

 

5 0
1 year ago
How many grams of sulfur must be burned to give 100.0 g of So2
andriy [413]

Answer:

50 g of S are needed

Explanation:

To star this, we begin from the reaction:

S(s) + O₂ (g) →  SO₂ (g)

If we burn 1 mol of sulfur with 1 mol of oxygen, we can produce 1 mol of sulfur dioxide. In conclussion, ratio is 1:1.

According to stoichiometry, we can determine the moles of sulfur dioxide produced.

100 g. 1mol / 64.06g = 1.56 moles

This 1.56 moles were orginated by the same amount of S, according to stoichiometry.

Let's convert the moles to mass

1.56 mol . 32.06g / mol = 50 g

4 0
2 years ago
Consider the element carbon. How many electrons can be found in a carbon atom? How many are valence electrons?
Eva8 [605]

Answer:

option B= 6 : 4

Explanation:

Properties:

1. Carbon have six electron and six proton.

2. The two electrons are present in first shell while remaining of four electrons are present in the second shell.

3. it is non-metallic element and present in the group fourteen of periodic table.

4. its atomic mass is 12.0107 u.

5. its melting and boiling point is 3550 °C and 4827 °C respectively.

Uses:

1. it is used as a fuel in the form of coal.

2. in the form of graphite it is used in dry cells, as a lubricant, in pencil and high temperature crucible.

3. it is also used in jewelry in the form of diamond and because of its hard nature used in industries for drilling, polishing, cutting and grinding.

4. carbon black powder is used in printer ink.

5. its most common alloy with iron is steel.

6. it form variety of compound with number of other elements like nitrogen, hydrogen, oxygen etc.

Electronic configuration:

1s2, 2s2, 2p2

Isotopes of carbon:

There are fifteen isotopes of carbon from C8 - C22. The isotopes  C12 and C13 are stable while C14 is radioactive.

4 0
3 years ago
How many grams of KCIO3 are needed to produce 5.00 of O2 at STP?
Arlecino [84]
2KClO₃ → 2KCl + 3O₂

mole ratio of KClO₃ to O₂ is 2 : 3

∴ if moles of O₂ = 5 mol

then moles of KClO₃ = \frac{5 mol   *   2}{3}

                            = 3.33 mol


Mass of KClO₃ needed = mol of KClO₃ × molar mass of KClO₃

                                      = 3.33 mol × ((39 × 1) + (35.5 × 1) + (16 × 3) g/mol

                                      = 407.93 g
6 0
2 years ago
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