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Alekssandra [29.7K]
2 years ago
5

How many moles are in 3.0x10^24 molecules of water​

Chemistry
2 answers:
Daniel [21]2 years ago
5 0
<h3>I HOPE MY ANSWER HELPS YOU;))</h3>

SpyIntel [72]2 years ago
5 0

Answer:

3.52 x 10^24 molecules x `1mol/6.02 x 10^23 molecules = 5.85 moles of H2O.

Explanation:

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1. Based on the observed performance of the air bag models and the amounts of sodium bicarbonate and acetic acid (vinegar) neede
Ira Lisetskai [31]

Sodium bicarbonate and acetic acid are not good substitute for sodium azide in airbags since the require more mass and produce less gas.

<h3>Which is the better chemical for an airbag?</h3>

The chemical equation for the production of nitrogen gas from sodium azide is given below:

  • NaN₃ → 2 Na + 3 N₂

1 mole or 66 go of sodium azide produces 3 moles or 67.2 L of nitrogen gas.

The equation for the production of carbon dioxide from sodium bicarbonate and acetic acid is given below:

  • Na₂CO₃ + CH₃COOH → CH₃COONa + CO₂ + H₂O

1 mole, 106 g of Na₂CO₃ and 1 mole, 82 g of CH₃COOH are required to produce 1 mole or 22.4 L of CO₂.

The mass of sodium azide required is less than that of sodium bicarbonate and acetic acid required. Also, sodium azide produces a greater volume of gas. Therefore, sodium bicarbonate and acetic acid are not good substitute for sodium azide in airbags.

In conclusion, sodium azide is a better choice in airbags.

Learn more about airbags at: brainly.com/question/14954949

#SPJ1

7 0
2 years ago
A chemical reference book says that substance x is not soluble in water
oksano4ka [1.4K]
<span>The normal dividing line for soluble/not soluble is 0.1 M. 

If a substance, as a saturated solution at room temp and pressure, cannot form a solution concentration of 0.1 M, then it is considered insoluble. 

The 0.1 M figure was selected because _most_ substances are either well above that value or well below. Some substances (calcium hydroxide is one? not sure) come close to the 0.1 M dividing line but there are only a very few.</span><span>  
but most likely it wont mix</span>
7 0
2 years ago
Write 6319857 in scientific notation
Anna71 [15]

Answer:

6.319857 * 10 to the power 7

5 0
3 years ago
Read 2 more answers
One mole of an ideal gas doubles its volume in a reversible isothermal expansion. (a) What is the change in entropy of the gas?
Andre45 [30]

Explanation:

The given data is as follows.

       n = 1 mol,     V_{f} = 2V_{i}

       Q = 1500 J,      R = 8.314 J/mol k

(a)    \Delta S = \frac{dQ}{dT}

And, according to the first law of thermodynamics

                \Delta E_{int} = Q - W

And, in an isothermal process the change in internal energy of the gas is zero.

Hence,    0 = Q - W

or,             W = Q

Expression for work done in an isothermal process is as follows.

                   W = nRT ln \frac{V_{f}}{V_{i}}

As W = Q, Hence expression for Q will also be given as follows.

            Q = nRT ln \frac{V_{f}}{V_{i}}

Now,  

        \Delta S = \frac{nRT ln \frac{V_{f}}{V_{i}}}{T}

        [/tex]\Delta S = nR ln \frac{V_{f}}{V_{i}}[/tex]

                      = nR ln \frac{2V_{i}}{V_{i}}

                       = nR ln 2

                        = 1 \times 8.314 \times 0.693

                        = 5.76 J/K

Therefore, change in entropy is 5.76 J/K.

(b)    As,  Q = nRT ln \frac{V_{f}}{V_{i}}

                   = nRT ln \frac{2V_{i}}{V_{i}}

                   = nRT ln 2

           T = \frac{Q}{nR ln 2}

              = \frac{1500}{1 \times 8.314 ln 2}

              = 260.4 K

Therefore, temperature of the gas is 260.4 K.

7 0
2 years ago
WEATHER PREDICTIONS FROM
fiasKO [112]

Answer:

These predictions are likely to be valid and should be needed.

Explanation:

Meteorologist made predictions about weather of a particular area on the data they received from the satellite. Meteorology is a branch of science in which we study about the atmosphere. It is mainly used for the forecasting of weather and meteorologists are those people or scientists who study the weather and research on different scales or instruments of weather.

7 0
3 years ago
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