Answer:
Beryllium
Explanation:
They are in the same group
<span>PBr5
You started with 0.72 mg of phosphorus and ended up with 10.01 mg of its bromide. So the amount of bromine is 10.01 - 0.72 = 9.29 mg
Now you need to determine the relative number of atoms of each element used.
atomic mass of phosphorus = 30.973762
atomic mass of bromine = 79.904
relative atoms of phosphorus = 0.72 / 30.973762 = 0.023245
relative atoms of bromine = 9.29 / 79.904 = 0.116265
Now you need to look for a simple ratio of integers that closely approximates 0.023245 / 0.116265. First we'll divide the larger by the smaller.
0.116265 / 0.023245 = 5.001597
Given how close the value comes to 5. The empirical formula will be PBr5. So for every atom of phosphorus, you need 5 atoms of bromine.</span>
Answer:
YASSSSSSS
Explanation:
i think the answer is true
