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IrinaVladis [17]
3 years ago
11

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Physics
2 answers:
Ronch [10]3 years ago
5 0

Answer:

Electric current

Explanation:

The others do not pertain to the flow of electrons. Positive current is the closest but it refers to the positive flow of electrons not just the flow of electrons.

Lady_Fox [76]3 years ago
4 0

Answer:

Electric Current

Explanation:

Electric current: An electric current is the rate of flow of electric charge past a point or region.

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Caculate the total charge transferred through a wire carrying a current of 0.5 Ameter for a period of 20 seconds.
Marina CMI [18]

charge = current x time = 0.5x 20=10Coulombs

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The diffusion coefficients for species A in metal B are given at two temperatures: T (°C) D (m2/s) 1020 8.01 × 10-17 1290 7.86×
Solnce55 [7]

Explanation:

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5 0
3 years ago
Consider the situation||: A child pulls a sled by a rope across the lawn at a constant speed. Of the forces listed, identify whi
Mice21 [21]

Answer:

Gravitational

Tension

Normal

Friction.

Explanation:

The forces acting on the sled are:

Tension: the tension from the rope, this is the force that "moves" the sled.

Friction: kinetic friction between the sled and the ground as the sled moves.

There are another two forces that also act on the sled, but that "has no effect"

Gravitational force: This force pulls the sled down, against the floor.

Normal force: This force "opposes" to the gravitational one, so they cancel each other.

These two forces cancel each other, so they have no direct impact on the movement of the sled. BUT, the friction force depends on the weight of the moving object, and the weight of the moving object depends on the gravitational force, so we need gravitational force in order to have friction force.

Then we can conclude that the forces acting on the sled are:

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6 0
2 years ago
The image shows one complete cycle of a mass on a spring in simple harmonic motion. An illustration of a mass on a vertical spri
Alja [10]

Answer:

D. "The net force is zero, so the acceleration is zero"

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edge 2020

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3 years ago
a 1500.0 kg car is at rest on a level track. The driver gives the engine gas and the car begins to accelerate forward. The car m
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Acceleration of the car is 3.375 m/s² and the force of the car moving forward is 5062.5 N

Explanation:

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Here, velocity changes from 0 to 27 m/s and time = 8

⇒ Acceleration = 27 - 0/8 = 27/8 = 3.375 m/s²

  • Force is calculated by the equation, F = Mass × Acceleration
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Here, mass of the car = 1500 kg and a = 3.375 m/s²

⇒ Force = 1500 × 3.375 = 5062.5 N

4 0
3 years ago
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