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3 years ago

Suppose a current flows through a copper wire. Which two things occur?

Physics

2 answers:

ICE Princess25 [194]3 years ago

4 0

Answer:

A) A magnetic field forms around the wire.

C) The field is perpendicular to the direction of flow of the current.

Explanation:

A.pex

worty [1.4K]3 years ago

3 0

I’m pretty sure the answer is c and d hope this helps and good luck

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How did early scientists attempt to organize the elements

Nookie1986 [14]

They organized them by color and size

8 0

3 years ago

Calculate A, E, μ, cv and S for 1 mole of Kr at 298 K and 1 atm (assuming ideal behavior)

vaieri [72.5K]

Answer:

internal energy E 3716.35 j

cv = 12.47 J/K

S = 12.47 J/K

A = 0.29 J

$\mu =3716.35 J/mole$

Explanation:

given data:

Kr atomic number = 36

degree of freedom = 3

1) internal energy E = $\frac{f}{2} n R T$

= $\frac{3}{2} *1*8.314*298 = 3716.35 j$

2) $cv = \frac{E}{T}$

$= \frac{3716.35}{298} = 12.47 J/K$

3) $S = cv =\frac{E}{T} = 12.47 J/K$

4) A, Halmholtz free energy = E -TS = 37146.35 - 12.47*298 = 0.29 J

5) $chemcial potential \mu = \frac{energy}{mole} = 3716.35 J/mole$

6 0

3 years ago

What is an example of a non contact force

olchik [2.2K]

Answer: Gravitational force

Explanation:

A non contact force can be described as a force applied to an object by another body that is not in direct contact with it.

For example, an object thrown upwards will return back due to the force of gravity acting on it. So, it means Gravitational force is acting on the body without necessarily being in contact with that body.

8 0

3 years ago

A 1.0 kg mass is attached to the end of a vertical ideal spring with a force constant of 400 N/m. The mass is set in simple harm

Marina86 [1]

Answer:

$v(0)=2m/s$

Explanation:

The instantaneous velocity of a point mass that executes a simple harmonic movement is given by:

$v(t)=\omega *A*cos(\omega t + \phi)$

Where:

$\omega=Angular\hspace{3}frequency\\A=Amplitude\\\phi=Initial\hspace{3}phase$

Express the amplitude in meters:

$10cm*\frac{1m}{100cm} =0.1m$

The angular frequency can be found using the next equation:

$\omega=\sqrt{\frac{k}{m} }$

Using the data provided:

$\omega=\sqrt{\frac{400}{1} } =20$

At the equilibrium position:

$\phi=0$

$v(0)=20*(0.1)cos(20*0+0)=2*cos(0)=2*1=2m/s$

6 0

3 years ago

Find the work w1 done on the block by the force of magnitude f1 = 75.0 n as the block moves from xi = -1.00 cm to xf = 3.00 cm .

MissTica

<span>The work done is 3.0 Nm. We can us the equation Work = Force * Distance, where Force = 75.0 N, and distance is xf â€“ xi = 3.00 cm - -1.00 cm = 4.00 cm. Convert centimeters to meters by moving the decimal place to the left by two places to get 0.04 m. Plug these values into the Work equation: Work = Force * Distance Work = 75.0 N * 0.04 m Work = 3.0 Nm</span>

5 0

3 years ago