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Illusion [34]
2 years ago
15

Suppose a current flows through a copper wire. Which two things occur?

Physics
2 answers:
ICE Princess25 [194]2 years ago
4 0

Answer:

A) A magnetic field forms around the wire.

C) The field is perpendicular to the direction of flow of the current.

Explanation:

A.pex

worty [1.4K]2 years ago
3 0
I’m pretty sure the answer is c and d hope this helps and good luck
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Need help with physics! Please provide explanation.
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2 years ago
Find the interest. A 105-day note for $14,200 at 8.5% interest.
mr Goodwill [35]
<h3><u>Answer</u>;</h3>

$347.22

<h3><u>Explanation</u>;</h3>

Principal = $14,200

Rate = 8.5%

Time = 105 days = 105/365

Interest = Principal x Rate x Time

Interest = 14,200 x 0.085 x 105/365

Interest = 347.219

             = $347.22

7 0
3 years ago
How does gravity affect the velocity of falling objects?
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7 0
3 years ago
You are performing a double slit experiment very similar to the one from DL by shining a laser on two nattow slits spaced 7.5 x
Blizzard [7]

Complete Question

You are performing a double slit experiment very similar to the one from DL by shining a laser on two nattow slits spaced 7.5 * 10^{-3} meters apart. However, by placing a piece of crystal in one of the slits, you are able to make it so that the rays of light that travel through the two slits are Ï out of phase with each other (that is to say, Ao,- ). If you observe that on a screen placed 4 meters from the two slits that the distance between the bright spot closest to center of the pattern is 1.5 cm, what is the wavelength of the laser?

Answer:

The  wavelength is  \lambda  =  56250 nm

Explanation:

From the question we are told that

   The  distance of slit separation is  d =  7.5 *10^{-3} \  m

   The  distance of the screen is  D =  4 \  m

    The  distance between the bright spot closest to the center of the interference  is  k   = 1.5 \ cm = 0.015 \  m

   

Generally the width of the central  maximum fringe produced is mathematically represented as

        y  =  2 *  k  = \frac{ D  *  \lambda}{d}

  =>    2 *  0.015 =  \frac{ \lambda  *  4}{ 7.5 *10^{-3}}

   =>   \lambda  =  56250 *10^{-9} \ m

=>      \lambda  =  56250 nm

7 0
3 years ago
You are on roller blades on top of a small hill. Your potential energy is equal to 1,000.0 joules. The last time
irinina [24]
It is -59 i think or just ask someone esle for help
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