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3 years ago

Suppose a current flows through a copper wire. Which two things occur?

Physics

2 answers:

ICE Princess25 [194]3 years ago

4 0

Answer:

A) A magnetic field forms around the wire.

C) The field is perpendicular to the direction of flow of the current.

Explanation:

A.pex

worty [1.4K]3 years ago

3 0

I’m pretty sure the answer is c and d hope this helps and good luck

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By counting the number of crests that pass in a given amount of time, a person can calculate the

ladessa [460]

By calculating the crests, you can find the waves' frequency.
Hope this helps!

3 0

3 years ago

Can someone help me in that plz ??!

olga_2 [115]

Answer: These forces are an example of newtons third law every action has equal and opposite reaction

Explanation:UwU

8 0

3 years ago

A ring is attached at the center of the underside of a trampoline. A sneaky teenager crawls under the trampoline and uses the ri

IRINA_888 [86]

Answer:

E = 301.5 J

Explanation:

We have,

Mass of mother, m = 67 kg

Here, a sneaky teenager crawls under the trampoline and uses the ring to pull the trampoline slowly down. As she passes through the position at which she was before her son stretched the trampoline, her speed is 3 m/s.

It is required to find the elastic potential energy the son add to the trampoline by pulling it down. It is based on the conservation of energy.

The elastic potential energy of the mother = the elastic potential energy the son add to the trampoline.

$\dfrac{1}{2}mv^2=\dfrac{1}{2}kx^2$

So, the elastic potential energy is :

$E=\dfrac{1}{2}mv^2\\\\E=\dfrac{1}{2}\times 67\times 3^2\\\\E=301.5\ J$

So, the elastic potential energy of 301.5 J the son add to the trampoline by pulling it down.

6 0

4 years ago

PLEASE HELPPPPP!!!! :)

GuDViN [60]

Answer:

F=X.F=mxq. 3. 1 N/kg=0.5kg g=9.80

4 0

3 years ago

If a spring with a spring constant k = 10 N/m is stretched from its equilibrium position by 0.1 m, and released, what would be t

inysia [295]

Answer:

0.05J

Explanation:

Since the total energy is conserved I.e the mechanical energy, the energy present in the system are kinetic energy, potential energy and the gravitational potential energy. The expression for this energy is written as

Kinetic Energy=1/2MV^2

Potential Energy=1/2Kx^2

Where K is the spring constant and X is the extension the spring experience.

Gravitational Energy=mgh

Where m=mass, g=gravity constant and h=height

Hence for a spring with spring constant 10N/m and extension 0.1m the potential energy can be calculated as

PE=1/2Kx^2

If we substitute values we arrive at

PE=1/2×10×0.1^2

PE=0.05J

6 0

3 years ago