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sergeinik [125]
4 years ago
15

The mass of a truck with its cargo is 1800 kg. The truck is coasting to the right with a speed of 10 m/s. As it coasts its cargo

of mass 300 kg is lifted up out of the truck by a crane. What will the velocity of the truck be after its cargo is taken off?
Physics
2 answers:
OverLord2011 [107]4 years ago
6 0

Here we apply conservation of linear momentum. The momentum of the truck with cargo and without cargo remains constant. That is,

mv=m'v'.

Here m,v are initial mass and velocity. m',v' are final mass and velocity. Here m=1800,v=10 and m'=1800-300=1500.

The velocity of the truck be after its cargo is taken off is

v'=\frac{mv}{m'} \\  v'=\frac{1800*10}{1500} \\  v'=12 m/s

timofeeve [1]4 years ago
6 0
I would round it out to be 15 ms or 20 good luck 

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Cart a having a mass of 150 kg initially moving to the right at a speed of 8 m/s collides with cart b with a mass of 150 kg, ini
kakasveta [241]

The speed of cart b is 6m/s while the total momentum of the systmen is 4200 kg m/s

<h3>Conservation of Linear Momentum</h3>

Given Data

  • Mass of cart one M1  = 150kg
  • Initial Velocity U1 = 8m/s
  • Final VelocityV1 = 5 m/s

Mass of cart two M2  = 150kg

Velocity U2 = 6m/s

Applying the principle of conservation of linear momentum we have

M1U1+M2U2 = M1V1+ M2V2

a. what is the speed of cart b after collision

substituting our given data we have

150*8+ 150*6 = 150*5+150*V2

1200 + 900 = 1200+ 150V2

2100 - 1200 = 150V2

900 = 150V2

Divide both sides by 150

V2 = 900/150

V2 = 6m/s

b. what is the total momentum of the system before and after collision

Total Momentum in the system is

Total momentum = Momentum before Impact+ Momentum after Impact

Total momentum = M1U1+M2U2 + M1V1+ M2V2

Total momentum = 1200 + 900 + 1200+ 900

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