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SVEN [57.7K]
3 years ago
13

2) A bully is pushing a boy against a locker as shown with a force of

Physics
1 answer:
polet [3.4K]3 years ago
5 0

Answer:

pull out the 9

Explanation:

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Physics is explicitly involved in studying which of these activities?
kozerog [31]
C is the answer hope it help
6 0
3 years ago
"if a 20 and a 40 ohm resistor are wired in parallel to a 20v source, what will be the current in the 40 ohm resistor?"
choli [55]

In parallel, neither resistor knows about the other one, and they have no effect on each other.

Each resistor is connected straight to the battery terminals. If the battery is hefty enough, it supplies current to each resistor as if the other one weren't there.

Current through a resistor = (voltage across it) / (its resistance).

Current = (20 V) / (40 ohms)

Current = 1/2 Ampere.

4 0
3 years ago
A 1.5 kg frictionless pendulum is released from point A at an angle θ of 35 degrees. The speed of the pendulum at point C is 3.4
sergeinik [125]

The length of the pendulum is 3.3 m.

The given parameters:

  • Mass, m = 1.5 kg
  • Angle, θ = 35⁰
  • Speed, v = 3.4 m/s

<h3>What is principle of conservation of energy?</h3>
  • The principle of conservation of energy states that, the total energy of a system is always conserved.

P.E = K.E

mgh = ¹/₂mv²

gh = ¹/₂v²

g(L - Lcosθ) = ¹/₂v²

gL(1 - cosθ) = ¹/₂v²

L = \frac{v^2}{2g(1- cos\theta)} \\\\L = \frac{(3.4)^2}{2\times 9.8(1 - cos35)} \\\\L = 3.28 \ m\\\\L = 3.3 \ m

Thus, the length of the pendulum is 3.3 m.

Learn more about length of pendulum here: brainly.com/question/8168512

3 0
3 years ago
Which statements best describe what is happening in the image?
olchik [2.2K]
Im afraid i cant help u if we can’t see the image u r working with. could u provide an image of the question?
8 0
3 years ago
Read 2 more answers
A force F = (cx - 3.00x^2)i^ acts on a virus as the virus moves along an x axis, with F measured in Newtons, x in meters, and c
Ket [755]

Answer:

c = 4

Explanation:

From work-energy theorem KE = workdone.

Given F = (cx - 3.00x²)i

W = ∫Fdx = ∫(cx - 3.00x²)dx = cx²/2 –3.00x³/3 + A

W = cx²/2 –x³ + A

Where A is a constant

At x = 0, KE = 20J

So W = 20J at x = 0

20 = c×0 - 0 +A

A = 20

So W = cx²/2 –x³ + 20

Also when x = 3.00m, W = KE = 11J

So

11 = c×3²/2 – 3³ + 20

11 = 4.5c – 7

4.5c = 11 + 7

4.5c = 18

c = 18/4.5 = 4

c = 4

6 0
4 years ago
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