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shusha [124]
3 years ago
5

We traveled all the way across the U.S. In some states, it rained; in others, it was hot and dry. But, the West Coast beaches we

re the best! What climate zone is being described?
tropical
temperate
polar
subtropical
Physics
2 answers:
nignag [31]3 years ago
8 0
The climate zone that is being described is Temperate
MakcuM [25]3 years ago
7 0

Answer:

The climate zone that is being described is the temperate zone.

Explanation:

Temperate climate is a climate found between the Arctic and the subtropical areas. Temperate climate areas usually have about the same length of summer as winter, but winter temperatures can vary.

In the hot-tempered climate, the average temperature in the coldest month will be between -3°C and 18°C, while the average temperature during the warmest month will be above 10°C.

In cold-temperate or boreal climates, the coldest month will be below -3 degrees Celsius, while the hottest month is still warmer than 10 degrees Celsius. Some areas with cold-temperate climates have extremely cold winters, especially this is the case in Siberia and inner parts of Canada.

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A4.0 kg object is moving with speed 2.0 m/s. A 1.0 kg object is moving with speed 4.0 m/s. Both objects encounter the same const
Evgesh-ka [11]

Answer:

Both objects travel the same distance.

(c) is correct option

Explanation:

Given that,

Mass of first object = 4.0 kg

Speed of first object = 2.0 m/s

Mass of second object = 1.0 kg

Speed of second object = 4.0 m/s

We need to calculate the stopping distance

For first particle

Using equation of motion

v^2=u^2+2as

Where, v = final velocity

u = initial velocity

s = distance

Put the value in the equation

0= u^2-2as_{1}

s_{1}=\dfrac{u^2}{2a}....(I)

Using newton law

a=\dfrac{F}{m}

Now, put the value of a in equation (I)

s_{1}=\dfrac{8}{F}

Now, For second object

Using equation of motion

v^2=u^2+2as

Put the value in the equation

0= u^2-2as_{2}

s_{2}=\dfrac{u^2}{2a}....(I)

Using newton law

F = ma

a=\dfrac{F}{m}

Now, put the value of a in equation (I)

s_{2}=\dfrac{8}{F}

Hence, Both objects travel the same distance.

6 0
3 years ago
A 200kg bumper car moving 3 m/s collides head on with a 392kg bumper car moving 6m/s. After impact, the larger car continues tra
Maru [420]

Answer:

the final speed of the smaller car is 5.624 m/s

Explanation:

Given;

mass of the small car, m₁ = 200 kg

initial velocity of the small car, u₁ = 3 m/s

mass of the larger car, m₂ = 392 kg

initial velocity of the larger car, u₂ = 6 m/s

final velocity of the larger car, v₂ = 1.6 m/s

let the direction of the larger car be positive

let the direction of the smaller car be negative

Apply the principle of conservation of linear momentum to determine the final speed of the smaller car.

m₁u₁ + m₂u₂ = m₁v₁  +  m₂v₂

200(-3)  +  392(6)  = 200v₁   +  392 x 1.6

-600 + 2352  = 200v₁    +  627.2

1752   =  200v₁     +   627.2

1752  -  627.2     =  200v₁

1124.8  = 200v₁

v₁  =  1124.8/200

v₁ = 5.624 m/s

Therefore, the final speed of the smaller car is 5.624 m/s

7 0
3 years ago
Work out the area of a rectangle with base, b=20mm and perimeter, p=50mm
Korvikt [17]

Answer:

100mm²

Explanation:

the other side: (50 - 20 × 2) ÷ 2 = 5

5 × 20 = 100

7 0
3 years ago
Read 2 more answers
How far can a person run in 15 minutes if he or she runs at an average speed of 16 km/hr
Studentka2010 [4]
4 km/hr. There are four quarters in an hour, so just divide 16 by 4 and you get 4. It is directly proportional.
6 0
3 years ago
a pitcher throws a .015 kg baseball from rest to a final velocity of 45. what is the magnitude of the change in momentum of the
BabaBlast [244]

Answer:

0.675 kg m/s

Explanation:

Momentum = mass x velocity

= 0.015 x 45 = 0.675 kg m/s

P.S. I'm not sure of this answer,  so it might be a good idea to check this with some other sources.

6 0
3 years ago
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