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Usimov [2.4K]
3 years ago
6

How far will Mr. Woodland’s pet coyote travel in 2 hours at an average speed of 28 km/he

Physics
1 answer:
Umnica [9.8K]3 years ago
3 0

Explanation:

no one is that I can get it to you tomorrow at the same time ago i used to

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DanielleElmas [232]

Answer:

Find answer below.

Explanation:

a. Group 2: alkaline earth metals. Some examples of alkaline earth metals are magnesium, calcium, barium, etc.

b. Transition metals: metals with unpredictable properties.

c. Chlorine: halogen.

d. Metalloid: make good semiconductors.

e. Group 1: alkali metals. These includes the soft, light and reactive chemical elements found in group 1 of the periodic table. Some examples are hydrogen, potassium, lithium, sodium, etc.

f. Noble gases: has a full outer energy level (shell). These are chemical elements with eight valence electrons and as such have a full octet. Some examples are argon, neon, etc.

h. Metal: loses electron in bonding. They usually lose electrons in order to attain a full outer energy level or noble gas electronic configuration.

5 0
3 years ago
2. What can you say about the acceleration of an object
mafiozo [28]

Answer:

inversely proportional

3 0
3 years ago
Read 2 more answers
Give reason.<br><br><br>b} String roller is an example of wheel and axel .Why?<br><br>​
Leokris [45]

Explanation:

string roller is called an example of wheel and axel because The thin rod which needs to be turned is called the axle and the wider object fixed to the axle, on which we apply force is called the wheel.

hence the we apply force on the roller and the string gets tight.

8 0
3 years ago
A skier with a 65kg mass skies down a 30 degree incline hill. The coefficient of friction is 0.1. a. Draw a free body diagram. b
djyliett [7]
B is the answer! Because no one would be pushing the rock all the way down the hill it would just go down by itself by rolling!!



Hope i helped plz mark as brainlist and 5 star'!
6 0
4 years ago
An internal combustion engine uses fuel, of energy content 44.4 MJ/kg, at a rate of 5 kg/h. If the efficiency is 28%, determine
Fudgin [204]
Efficiency =  Power Output / Power Input

Power Input = Rate of Energy input = 44.4 MJ/kg * 5 kg/h

 = 222 MJ/h

But 1 hour = 3600seconds

222 MJ/h = 222 MJ/3600s =  0.061667 MW              J/s = Watts

Power input = 0.061667 MW = 61 667 W

From  Efficiency =  Power Output / Power Input

   28% =  Power Output / 61667

   Power Output = 0.28 * 61667

   Power Output = 17266.76 W
 
  Power Output = 17 267 W

 Rate of heat Rejection = Power input - Power output

                                        = 61667 - 17267 = 44400 W

Rate of heat Rejection = 44 400 W.


C- Copyright.
5 0
3 years ago
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