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pshichka [43]
3 years ago
7

A convex lens of focal length 35 cm produces a magnified image 2.5 times the size of the object. What is the object distance if

the image (formed) is real?
Physics
1 answer:
Zanzabum3 years ago
3 0

Answer:

Image distance is -52.5 cm

Image is virtual and forms on the same side of the lens and upright image is formed.

Explanation:

u = Object distance

v = Image distance

f = Focal length = 35

m = Magnification = 2.5

m=-\frac{v}{u}\\\Rightarrow 2.5=-\frac{v}{u}\\\Rightarrow v=-2.5 u

Lens equation

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{35}=\frac{1}{u}+\frac{1}{-2.5u}\\\Rightarrow \frac{1}{35}=\frac{3}{5u}\\\Rightarrow u=21\ cm

v=-2.5\times 21=-52.5\ cm

Image distance is -52.5 cm

Image is virtual and forms on the same side of the lens and upright image is formed.

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: A 70 kg man and a 12 kg sled are on the frictionless ice of a frozen lake, 25 m apart but connected by a rope of negligible ma
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x_1 = 3.74m

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