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Alex17521 [72]
3 years ago
6

if the coefficient of linear expansion of a metal is 2.05× 10^-6 k^-1 what will be its new length if 50cm metal went through a t

emperature charge of 50°C?​
Physics
1 answer:
boyakko [2]3 years ago
7 0

Answer:

L = L0 (1 + c T)   where c is the coefficient and T the change in temperature

L = 50 ( 1 + 2.05E-6 * 50) = 50.0051 cm

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In a certain region of space, a uniform electric field has a magnitude of 4.30 x 104 n/c and points in the positive x direction.
denis23 [38]
The magnetic force exerted by a field E to a charge q is given by F=Eq. In this case, F=4.30*10^4*(6.80mu C). 1mu C=10^-6C, so F=4.30*6.80=10^-2=0.29N. The direction is in the x direction, the direction that the field is applied because the charge is positive.
5 0
4 years ago
Two vectors are illustrated in the coordinate plane.
oksano4ka [1.4K]

Answer: (-4.3, 2.5)

Explanation:

In the second quadrant, magnitude of the vector is 5 and angle is 30° from the negative x-axis.

We can write this in terms of its components:

-5 cos 30^o \hat i + 5 sin 30^o\hat j

-4.3\hat i+2.5 \hat j

Thus, the components of vector in the second quadrant are (-4.3, 2.5)

4 0
3 years ago
You use 35 J of energy to move a 7.0 N object. How far did you move it?
Lesechka [4]

The object has  been moved by 5 m

Explanation:

The work done by a force when moving an object (which is equal to the energy used to move the object) is given by

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement of the object

\theta is the angle between the direction of the force and of the displacement

In this problem, we have

W = 35 J is the work done

F = 7.0 N is the magnitude of the force

\theta=0^{\circ}, assuming the force is applied parallel to the direction of motion of the object

Therefore, we can solve the formula for d to find the displacement of the object:

d=\frac{W}{F cos \theta}=\frac{35}{(7)(cos 0)}=5 m

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

6 0
4 years ago
L 2.5.2 Test (CST): The Brain and the Body
ahrayia [7]

Answer:

I believe it's A frontal. Hope this can help

8 0
3 years ago
A 1.3-kg book rests on a table. A downward force of 15 N is exerted on the top of the book by a hand pushing down on the
garri49 [273]

Answer:

The net force will be:

F_{net} = 142.53\: N

Explanation:

The net force is given by:

F_{net} = W_{b}+F

F_{net} = m_{b}g+15

F_{net} = 142.53\: N

I hope it helps you!

                 

7 0
3 years ago
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