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amid [387]
3 years ago
11

How does the speckled coat of a young deer help it to survive?

Chemistry
2 answers:
nadya68 [22]3 years ago
7 0

Answer:

The answer is D

Explanation:

RoseWind [281]3 years ago
3 0
The answer is D, The speckled coat helps them camouflage into the environment  <span />
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Write the balanced equation for the reaction of acetic acid (CH3COOH) and sodium bicarbonate (NaHCO3). What type of reaction(s)
stealth61 [152]

Answer:CH3COOH + NaHCO3 > H2O + CO2(g) + CH3COONa

Explanation:acid and base neutralize creating water and CO2 gas along with a salt

5 0
3 years ago
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A neutral atom has 8 electrons and 8 neutrons. Which of the following correctly represents the atom? A) carbon-16 B) oxygen-16 C
bija089 [108]

Answer:

D

Explanation:

Oxygen is the 8th element in the periodic table. This means that oxygen has 8 protons and 8 electrons. In order to get the number of neutrons you take the atomic weight in this case 15.9999~16 and you subtract it by the number of protons (16-8).

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What particle decay is this? 210 83 Bi→210 84 Po ​
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Answer:

Beta emission

Explanation:

In beta emission, a neutron is converted into a proton thereby emitting an electron and a neutrino. A neutrino is a particle that serves to balance the spins.

When a nucleus undergoes beta emission, the mass number of the parent and daughter nuclei remain the same while the atomic number of the daughter nucleus is greater than that of its parent by one unit.

Hence, in beta emission, the daughter nucleus is found one pace to the right of the parent in the periodic table.

3 0
3 years ago
Calculate the amount of oxygen gas collected by the displacement of water at 14◦C if the atmospheric pressure is 790 Torr and th
zhannawk [14.2K]

Answer : The amount of oxygen gas collected are, 0.217 mol

Explanation :

Using ideal gas equation :

PV=nRT

where,

P = pressure of gas = (790-12)torr=778torr=1.02atm     (1 atm = 760 torr)

V = volume of gas = 5 L

T = temperature of gas = 14^oC=273+14=287K

n = number of moles of gas = ?

R = gas constant  = 0.0821 L.atm/mol.K

Now put all the given values in the ideal gas equation, we get:

(1.02atm)\times (5L)=n\times (0.0821L.atm/mol.K)\times (287K)

n=0.217mole

Thus, the amount of oxygen gas collected are, 0.217 mol

8 0
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8 0
3 years ago
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