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kow [346]
3 years ago
6

What compound is YCI3

Chemistry
1 answer:
Damm [24]3 years ago
8 0

Answer:

Yttrium, Carbon, Iodine

Explanation:

Y stands for Yttrium

C stands for Carbon

I stands for Iodine

and 3 stands for 3 Iodine atoms

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(part 1 of 3) Copper reacts with silver nitrate through a single replacement. If 1.29 g of silver are produced from the reaction
ale4655 [162]

Answer:

See explanation.

Explanation:

Hello there!

In this case, according to the described chemical reaction, we first write the corresponding equation to obtain:

Cu+2AgNO_3\rightarrow 2Ag+Cu(NO_3)_2

Thus, we proceed as follows:

Part 1 of 3: here, since the molar mass of silver and copper (II) nitrate are 107.87 and 187.55 g/mol respectively, and the mole ratio of the former to the latter is 2:1, we can set up the following stoichiometric expression:

m_{Cu(NO_3)_2}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{1molCu(NO_3)_2}{2molAg}*\frac{187.55gCu(NO_3)_2}{1molCu(NO_3)_2}   \\\\m_{Cu(NO_3)_2}=1.12gCu(NO_3)_2

Part 2 of 3: here, the molar mass of copper is 63.55 g/mol and the mole ratio of silver to copper is 2:1, the mass of the former that was used to start the reaction was:

m_{Cu}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{1molCu}{2molAg}*\frac{63.55gCu)_2}{1molCu}   \\\\m_{Cu}=0.380gCu

Part 3 of 3: here, the molar mass of silver nitrate is 169.87 g/mol and their mole ratio 2:2, thus, the mass of initial silver nitrate is:

m_{AgNO_3}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{2molAgNO_3}{2molAg}*\frac{169.87gAgNO_3}{1molAgNO_3}   \\\\m_{AgNO_3}=2.03gAgNO_3

Best regards!

5 0
3 years ago
Need help asap!!!!<br> will mark brainliest!!!
SOVA2 [1]

Answer:

picture not bright

Explanation:

please a brainliest for tge feedback

7 0
2 years ago
What is the element with the symbol Ba?​
Vika [28.1K]

Answer:

Barium

Explanation:

-Atomic #56

-5th element inn group 2

- soft

- silvery alkaline earth metal

3 0
3 years ago
Read 2 more answers
Calculate the mass of sucrose needed to prepare a 2000 grams of 2.5% sucrose solution.
meriva

Answer:

50 g Sucrose

Explanation:

Step 1: Given data

  • Mass of solution: 2000 g
  • Concentration of the solution: 2.5%

Step 2: Calculate the mass of sucrose needed to prepare the solution

The concentration of the solution is 2.5%, that is, there are 2.5 g of sucrose (solute) every 100 g of solution. The mass of sucrose needed to prepare 2000 g of solution is:

2000 g Solution × 2.5 g Sucrose/100 g Solution = 50 g Sucrose

5 0
2 years ago
Is the sun typical of these nearby stars
marshall27 [118]
No the sun is the biggest star in the universe.
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3 years ago
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