Question 6 of 10

Mathematics

1 answer:

Ivan3 years ago

4 0

Answer:

5
Sabihin mo po Kung mali

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Which parallelogram has an area of 60 square units? Select the correct

faust18 [17]

Wait what is what which number goes to what letter

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3 years ago

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STALIN [3.7K]

Hi there! The answer is C.

Explanation:
We have the following equation:

$\frac{8}{15} = \frac{x}{6}$
To solve this type of equation (with an x in the denominator of a fraction) we must cross-multiply the numerator and the denominator.

$15 \times x = 8 \times 6$
Multiply

$15x = 40$
Divide both sides by 15.

$x = \frac{40}{15} = 2 \frac{2}{3}$
~ Hope this helps you!

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Javed downloaded from the Internet two files that had a combined size of 696 megabytes. The size of the first file was 290 megab

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Please help with this problem.

larisa86 [58]

Answer:

60°, 120°

Step-by-step explanation:

$\frac{ {tan}^{2}x }{2} - 2 {cos}^{2}x = 1 \\ \\ \frac{ {tan}^{2}x - 4{cos}^{2}x }{2} = 1 \\ \\ {tan}^{2}x - 4{cos}^{2}x = 2 \\ \\ \frac{{sin}^{2}x}{{cos}^{2}x} - 4{cos}^{2}x = 2 \\ \\ \frac{{sin}^{2}x - 4{cos}^{4}x}{{cos}^{2}x} = 2 \\ \\ {sin}^{2}x - 4{cos}^{4}x = 2{cos}^{2}x \\ \\ 4{cos}^{4}x + 2{cos}^{2}x - {sin}^{2}x = 0 \\ \\ 4{cos}^{4}x + 2{cos}^{2}x + {cos}^{2}x - 1= 0 \\ \\ 4{cos}^{4}x + 3{cos}^{2}x - 1= 0 \\ \\ 4{cos}^{4}x + 4{cos}^{2}x - {cos}^{2}x - 1= 0 \\ \\4{cos}^{2}x({cos}^{2}x + 1) - 1({cos}^{2}x + 1) = 0 \\ \\ ({cos}^{2}x + 1)(4{cos}^{2}x - 1) = 0 \\ \\ ({cos}^{2}x + 1) = 0 \: or \: (4{cos}^{2}x - 1) = 0 \\ \\ {cos}^{2}x = - 1 \: or \: 4{cos}^{2}x = 1 \\ \\ {cos}x = \sqrt{ - 1} \: which \: is \: not \: possible \\ \therefore \: {cos}^{2}x = \frac{1}{4} \\ \\ \therefore \: {cos}x = \pm\frac{1}{2} \\ \\ \therefore \: {cos}x = \frac{1}{2} \: or \: {cos}x = - \frac{1}{2} \\ \\ \therefore \: {cos}x = {cos}60 \degree \: or \: {cos}x = {cos}120 \degree \\ \\ \therefore \:x = 60 \degree \: \: or \: \: x = 120 \degree$

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Which expression would be equivalent if you expanded −2(−8x+12y)?

Romashka-Z-Leto [24]

Answer:

16x-24y

Step-by-step explanation:

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