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daser333 [38]
2 years ago
7

DESPERATE WILL GIVE BRAINLIST AND THANKS

Chemistry
1 answer:
Annette [7]2 years ago
8 0

Answer:

20 grams

Explanation:

40g= 300

x = 150

cross multiply, 40*150/300

6000/300= 20g

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What property of water allows it to stick to a dry surface
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You are looking for ADHESION
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Rank the elements according to highest ionization energy:<br><br> Be, C, O, Ne, B, Li, F, N
aleksklad [387]
Given:
Be - Beryllium   -   9,3227
C   - Carbon      - 11,2603
O   - Oxygen      - 13,6181
Ne - Neon          - 21,5645
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5 0
3 years ago
Read 2 more answers
what is the structure of XeO2F2???i know its hybridization as sp3d but cannot quite understand its diagram in free space,help an
skelet666 [1.2K]
The shape of XeO₂F₂ is Trigonal bi-pyramidal see-saw tetrahedron (see attached pictures)
- As you said the hybridization of Xe here is sp³d so its geometry has to be Trigonal bi-pyramidal in which F atom located on axial positions but for the final shape we exclude lone pair on Xe to give see-saw shape (see second picture) 
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6 0
3 years ago
When 60 mL of 0.22 M NH4Cl is added to 60 mL of 0.22 M NH3, relative to the pH of the 0.10 M NH3 solution the pH of the resultin
densk [106]

Answer:

Will be more acidic

Explanation:

The equilibrium of NH3 in water is:

NH3(aq) + H2O(l) ⇄ NH4⁺(aq) + OH⁻(aq).

Where equilibrium constant, Kb, is:

Kb = 1.85x10⁻⁵ = [NH4⁺] [OH⁻] / [NH3]

From 0.10M NH3, the reaction will produce X of NH4⁺ and X of OH⁻ and Kb will be:

1.85x10⁻⁵ = [X] [X] / [0.10M]

1.8x10⁻⁶ = X²

X = 1.34x10⁻³ = [OH⁻]

As pOH = -log[OH⁻] = 2.87

And as pH = 14 - pOH

pH of the 0.10M NH3 is 11.13

Now, to find the pH of the NH4Cl and NH3 we need to use H-H equation for bases:

pOH = pKb + log [NH4⁺] / [NH3]

<em>Where pKb is -log Kb = 4.74 and [] are moles of both compounds.</em>

<em />

Moles of [NH4⁺] = [NH3] = 60mL, 0.060L*0.22M = 0.0132moles:

pOH = 4.74 + log [0.0132] / [0.0132]

pOH = 4.74

pH = 14 - 4.74 = 9.26

That means the pH of the resulting solution will be more acidic

7 0
3 years ago
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