Answer:
help with mine ill help with yours
The Rutherford–Bohr model of the hydrogen atom (Z = 1) or a hydrogen-like ion (Z > 1). In this model it is an essential feature that the photon energy (or frequency) of the electromagnetic radiation emitted (shown) when an electron jumps from one orbital to another, be proportional to the mathematical square of atomic charge (Z2). Experimental measurement by Henry Moseley of this radiation for many elements (from Z = 13 to 92) showed the results as predicted by Bohr. Both the concept of atomic number and the Bohr model were thereby given scientific credence. The atomic number is the number of _z_ an atom.
The answer is A but i'm not sure .
The Calcium ion is an Alkaline earth metal and wants to give up the 2 s orbital elections and become a +2 cation.
Oxygen has six valence electrons and is looking to gain two electrons to complete the octet (8) electron count in the valence shell making it a -2 anion.
When the charges of the Calcium +2 and the Oxygen -2 are equal and opposite, the ions for an electrical attraction. (Remember Paula Abdul told us "Opposites Attract")
This one to one ratio of charges makes the formula CaO
Answer:
55.5g of N₂
Explanation:
It is possible to find ΔH of a reaction by the sum of half-reaction (Hess's law), thus:
<em>(1) </em>4 NH₃ + 3 O₂ → 2 N₂ + 6 H₂O ΔH= -1556KJ
<em>(2) </em>N₂O + H₂ → N₂ + H₂O ΔH= -389.4 KJ
<em>(3) </em>H₂+ ½ O₂ → H₂O ΔH= -223.9 KJ
(4) = 1/2 (1) + 3 (2):
<em>(4) </em>2 NH₃ + 3 N₂O +3 H₂ + ³/₂ O₂ → 4 N₂ + 6 H₂O
ΔH = 1/2 (-1556kJ) + 3 (-389.4kJ) = -1946.2kJ
(4) - 3(3):
2 NH₃ + 3 N₂O → 4 N₂ + 3 H₂O ΔH = -1946.2kJ - 3 (-223.9 KJ)
ΔH = -1274.5 kJ
As when 5 moles of nitrogen are produced there are released 1274.5kJ, when are released 505kJ:
505kJ × (5 moles N₂ / 1274.5kJ) =<em> 1.98 moles of N₂. </em>In mass:
1.98moles N₂ ₓ (28g / 1mol) = <em>55.5g of N₂</em>