pH of 0.40M triethylammonium chloride is 5.90.
<h3>What is pH?</h3>
A solution's acidity may be determined by looking at its pH, which is a measurement of hydrogen ion concentration. Pure water slightly separates into ions with roughly equal amounts of hydrogen and hydroxyl (OH) ions. [H+] is 107 for a neutral solution, or pH = 7.
<h3>Given : </h3>
Concentration of triethylammonium chloride = 0.40M
pH = ?
<h3>Solution: </h3>
(CH3CH2)3NHCl ------> (CH3CH2)3NH⁺ + Cl⁻
(CH3CH2)3NH⁺ will react with water to give H3O⁺ .
(CH3CH2)3N will have a Kb = 5.2 x 10 ^(-4)
Kw = Kb x Ka
=> Ka = Kw / Kb = 10^(-14) / 5.2 x 10 ^(-4)
=> Ka = 1.92 x 10^(-11)
so by the reaction we have ,
Ka = x²/(0.40 - x)
=> x = 1.2393 x 10 ^(-6)
now, pH = -log( [H3O⁺]) = - log ( 1.2393 x 10 ^(-6)) = 5.906
To learn more about pH :
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Answer:
The heat generated per gram of sample in calories is 0.87 g
Explanation:
Given that,
A calorimeter made from a can is used to measure the calories in a peanut.
During the experiment, the measured calories were 35% of the true/accepted value given by references
Suppose, the mass of peanut is 0.4 g and find the
We need to calculate the heat generated per gram of sample in calories
Using formula of heat generated

Put the value into the formula


Hence, The heat generated per gram of sample in calories is 0.87 g
They have no charge and are located inside the nucleus
Answer : The expression for solubility constant for this reaction will be,
![K_{sp}=[Ca^{2+}]^3[PO_4^{3-}]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BCa%5E%7B2%2B%7D%5D%5E3%5BPO_4%5E%7B3-%7D%5D%5E2)
Explanation :
Solubility product : It is defined as the product of the concentration of the ions that present in a solution raised to the power by its stoichiometric coefficient in a solution of a salt. This takes place at equilibrium only.
The solubility product constant is represented as,
.
The dissociation of calcium phosphate is written as:

The expression for solubility constant for this reaction will be,
![K_{sp}=[Ca^{2+}]^3[PO_4^{3-}]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BCa%5E%7B2%2B%7D%5D%5E3%5BPO_4%5E%7B3-%7D%5D%5E2)