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Lilit [14]
4 years ago
13

N2 + 3H2 mc011-1.jpg 2NH3 What is the mole ratio of hydrogen to ammonia?

Chemistry
2 answers:
hjlf4 years ago
3 0
1 N₂ + 3 H₂ = 2 NH₃

Mole  ratio <span> of hydrogen to ammonia :

3 moles H</span>₂  :  2 moles NH₃   or  3 : 2

hope this helps!
Vedmedyk [2.9K]4 years ago
3 0

Answer : The mole ratio of hydrogen to ammonia is, 3 : 2

Explanation :

Balanced chemical reaction : The chemical reaction in which the number of individual atoms of an element present on the reactant side always be equal to the number of individual atoms of an element present on the product side.

The given balanced chemical reaction is,

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

From the balanced chemical reaction, we conclude that 1 mole of N_2 gas react with 3 moles of H_2 gas to give 2 moles of NH_3 gas as a product.

The mole ratio of nitrogen, hydrogen and ammonia is, 1 : 3 : 2

Therefore, the mole ratio of hydrogen to ammonia is, 3 : 2

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Viefleur [7K]
The Correct answer to this question is translation
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3 years ago
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If a large marshmallow has a volume of 2.50 i n 3 and density of 0.242 g/c m 3 , how much would it weigh in grams? 1 i n 3 =16.3
Illusion [34]

Density of a substance is defined as the mass of the substance divided by the volume.

Density of the substance= 0.242 g cm⁻³  

volume of the substance= 2.50 in³  

As, 1 in³= 16.39 cm³  

So, 2.50 in³= 16.39× 2.50 cm³=40.97 cm³

As ,  

Density=\frac{mass}{volume}  

Mass=volume ×Density

Mass=40.97 × 0.242

Mass=9.916 g.

4 0
4 years ago
I need help on this<br>all of them plz
yaroslaw [1]
For the first question it would be a unit obtained from the change in velocity per unit of time or m/s^2.

The vf and vi represent the final and initial velocity of the object and or item.

Knowing the formula for acceleration is simply change in velocity divided by time

Vi = 0
Vf = 27 m/s
t = 10 s

Vf = vi + at

27 = 10a

a = 27/10 or 2.7 m/s^2.
6 0
4 years ago
What is the best kind of cleaning agent to use for cleaning burned-on grease?
lakkis [162]

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4 years ago
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If 309 grams of potassium combines with 228 g chlorine gas, how many grams of the single product will be formed? What are the LR
lisov135 [29]

The amount of KCl that would be formed will be 478.8 grams

<h3>Stoichiometric calculations</h3>

From the equation of the reaction, the mole ratio of K to Cl_2 is 2:1.

Mole of 309 g potassium = 309/39 = 7.92 moles

Mole of 228 g Cl2 = 228/71 = 3.21 moles

Thus, potassium is in excess while Cl2 is limiting.

Mole ratio of Cl2 and KCl = 1:2

Equivalent mole of KCl = 3.21 x 2 = 6.42 moles

Mass of 6.42 moles KCl = 6.42 x 74.55 = 478.8 grams

More on stoichiometric calculations can be found here: brainly.com/question/27287858

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4 0
2 years ago
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