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ivann1987 [24]
2 years ago
15

What is the percent yield of the purification system

Chemistry
1 answer:
Jlenok [28]2 years ago
3 0

Answer: 90.3

Explanation:

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A gas balloon has a volume of 80.0 mL at 300K, and a pressure of 50.0 kPa. If the pressure changes to 80 kPa and the temperature
fomenos

Answer:  The new volume is 53.3 ml

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas =  50.0 kPa

P_2 = final pressure of gas = 80.0 kPa

V_1 = initial volume of gas = 80.0 ml

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 300K

T_2 = final temperature of gas = 320K

Now put all the given values in the above equation, we get:

\frac{50.0\times 80.0}{300}=\frac{80.0\times V_2}{320}

V_2=53.3ml

The new volume is 53.3 ml

4 0
2 years ago
Two identical pots, one black and one silver, containing exactly the same amounts of water, are heated to the same temperature.
I am Lyosha [343]
The most probable answer is: (a) <span>The black pot emits heat at a faster rate than the silver pot. It means the black pot conducts heat at a higher rate than the silver pot, that's why it cooled off faster. It also means that the silver pot retains heat better and is more of an insulator.</span>
7 0
3 years ago
Read 2 more answers
So I am lost and I don't know how what any of those conversion factor things are and I'm wondering how to do #2,3, and 4. (I did
dalvyx [7]

Explanation:

#2.

A centigram is 1/100 of a gram, so that means a gram equals 100 centigrams.

Therefore you multiply 72.4 grams by 100/1 (or just 100), and get 7240 cg.

You did that one right but put the wrong unit in the answer. It is is cg ( centigrams).

#3.

1 liter is equal to 1000 milliliters, and I kiloliter is equal to 1000 liters. So one kiloliter is 1000*1000 milliliters or 1,000,000 milliliters.

The conversion factor would be

1/1000000

#4.

1 gigabyte is equal to 10^9 bytes.

I byte is equal to 10^9 bytes.

So 1 gigabyte is 10^9 * 10^9 nanobytes, or 10^18.

The conversion factor would be (1*10^18)/1.

6 0
3 years ago
If the density of pure water is 0.9922 g/mL at 40 ºC, calculate its theoretical molarity at that temperature. Report to 4 sig fi
OleMash [197]
Answer is: theoretical molarity of water is 55.1222 mol/L.<span>
d(H</span>₂O) = 0.9922 g/mL.
M(H₂O) = 2 · Ar(H) + Ar(O) · g/mol.
M(H₂O) = 2 + 16 · g/mol = 18 g/mol.
c(H₂O) = d(H₂O) ÷ M(H₂O).
c(H₂O) = 0.9922 g/mL ÷ 18 g/mol.
c(H₂O) = 0.0551 mol/mL.
c(H₂O) = 0.0551 mol/mL · 1000 mL/L = 55.1222 mol/L.
3 0
3 years ago
What would the word equation be?
valentinak56 [21]
The problem=the equation
5 0
3 years ago
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