All categories

2 years ago

Find the final product for: Li + Br and show work.

Chemistry

1 answer:

miskamm [114]2 years ago

7 0

Lithium is atomic number 3, so it has valency 1

While, Bromine is atomic number 35, and has valency 1

Lithium has an extra electron while Bromine need an electron, since they both need and have one electron, the form

LiBr (Lithium Bromide) where Li is +ve charged and Br is -ve charged

Happy to help :)

You might be interested in

what happens when baking soda is mixed with vinegar a a new substance is formed B the substances are the same c but the baking s

Ray Of Light [21]

Answer:

NaHCO3 sodium bicarbonate is baking soda; added to the acetic acid, it forms sodium acetate (aqueous), CO2 gas & water. Remove the water & solid sodium acetate remains.

Explanation:

5 0

3 years ago

In Part III, the phenolphthalein indicator is used to monitor the equilibrium shifts of the ammonia/ammonium ion system. The phe

AnnZ [28]

The pink color in the solution fades. Some of the colored indicator ion converts to the colorless indicator molecule.

<h3>Explanation</h3>

What's the initial color of the solution?

$\text{NH}_4\text{Cl}$ is a salt soluble in water. $\text{NH}_4\text{Cl}$ dissociates into ions completely when dissolved.

$\text{NH}_4\text{Cl} \; (aq)\to {\text{NH}_4}^{+} \; (aq) +{\text{Cl}}^{-} \; (aq)$ .

The first test tube used to contain $\text{NH}_4\text{OH}$ . $\text{NH}_4\text{OH}$ is a weak base that dissociates partially in water.

$\text{NH}_4\text{OH} \; (aq) \rightleftharpoons {\text{NH}_4}^{+} \;(aq)+ {\text{OH}}^{-} \; (aq)$ .

There's also an equilibrium between $\text{OH}^{-}$ and ${\text{H}_3\text{O}}^{+}$ ions.

${\text{OH}}^{-}\;(aq) + {\text{H}_3\text{O}}^{+} \;(aq) \to 2\; \text{H}_2\text{O} \;(l)$ .

$\text{OH}^{-}$ ions from $\text{NH}_4\text{OH}$ will shift the equilibrium between $\text{OH}^{-}$ and ${\text{H}_3\text{O}}^{+}$ to the right and reduce the amount of ${\text{H}_3\text{O}}^{+}$ in the solution.

The indicator equilibrium will shift to the right to produce more ${\text{H}_3\text{O}}^{+}$ ions along with the colored indicator ions. The solution will show a pink color.

What's the color of the solution after adding NH₄Cl?

Adding $\text{NH}_4\text{Cl}$ will add to the concentration of ${\text{NH}_4}^{+}$ ions in the solution. Some of the ${\text{NH}_4}^{+}$ ions will combine with $\text{OH}^{-}$ ions to produce $\text{NH}_4\text{OH}$ .

The equilibrium between $\text{OH}^{-}$ and ${\text{H}_3\text{O}}^{+}$ ions will shift to the left to produce more of both ions.

${\text{OH}}^{-}\;(aq) + {\text{H}_3\text{O}}^{+} \;(aq) \to 2\; \text{H}_2\text{O} \;(l)$

The indicator equilibrium will shift to the left as the concentration of ${\text{H}_3\text{O}}^{+}$ increases. There will be less colored ions and more colorless molecules in the test tube. The pink color will fade.

7 0

3 years ago

If you need to measure the mass of a greeting card you are sending to a friend through the mail, what unit of measurement would

erica [24]

You would use grams to measure ot

4 0

3 years ago

The name of a binary compound ends with _____.<br><br> A.-ine<br> B.-ary<br> C.-ed<br> D.-ide

inn [45]

Cant really explain, for say, but its D.-ide

gfd
gd
fg
fg
g
ds
gf
df
gd
g

7 0

3 years ago

1,5,25,125 what’s the pattern rule and extend by 3 more numbers

nika2105 [10]

For the first one the pattern is multiply the previous number by five as you see 1 x 5 = 5 and so on. To keep adding to it you would do

125 x 5 = 625 625 x 5 = 3125 3125 x 5 = 15625

Now for the second one the pattern is divide the previous number by three as you can see 2187 / 3 = 729 and so on. To keep going you would

81 / 3 = 27 27 / 3 = 9 9 / 3 = 3

I hope this helps you and if you have anymore questions i'll be glad to answer them.

4 0

3 years ago