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3 years ago

BC =using the Distance Formula

Mathematics

1 answer:

riadik2000 [5.3K]3 years ago

5 0

Answer: Option A: 5

Step-by-step explanation:

If yo have the pairs (a, b) and (c, d)

The distance between these two points is:

distance = √( (a - c)^2 + (b - d)^2)

Here we want to find the distance between points B and C.

We can see that the coordinates of each one are:

point B: (-5, 5)

Point C: (-1, 2)

Then the distance between these points is:

AB = √( (-5 -(-1))^2 + (5 -2)^2) = 5

AB = √( 4^2 + 3^2)

Then the correct option is A

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3 years ago

Please help me graph and find the slope. I need an answer ASAP will mark brainliest!

Xelga [282]

Answer:

y = 0.6x

Step-by-step explanation:

Slope Formula: $m=\frac{y_2-y_1}{x_2-x_1}$

Slope-Intercept Form: y = mx + b

Step 1: Find slope <em>m</em>

m = (1.2 - 0)/(2 - 0)

m = 1.2/2

m = 0.6

y = 0.6x

Step 2: Find y-intercept <em>b</em>

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Step 3: Graph

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3 years ago

What is "The relationship between time and the distance Remaining on a 3 mile walk for someone walking at a steady rate of 2 mph

FromTheMoon [43]

Answer:

Let d be the remaining distance.

Let t be the remaining time.

The standard distance equation is:

d = rt

We are given the rate as 2, so:

d = 2t

At the start of the walk, the remaining distance is 3 miles.

The remaining time is 1.5 hours.

At the end of the walk, the remaining distance is 0 miles.

The remaining time is 0 hours.

A graph of the distance and time would be a continuous, solid line. That's because the walker will be at every distance between 3 and 0 and every time between 1.5 and 0.

Answer:

The graph of this would be a solid line

5 0

3 years ago

PLEASE PLEASE HELP! Find the measure of APB^.

Whitepunk [10]

Answer:

65°

Step-by-step explanation:

Radii CA and CB are perpendicular to tangent lines AT and BT, so

$\angle CAT=\angle CBT=90^{\circ}$

Since angle BAT is equal to 65°, angle CAB has measure

$\angle CAB=90^{\circ}-65^{\circ}=25^{\circ}.$

Consider triangle ACB. This triangle is isosceles, because CA=CB as radii of the circle. Two angles adjacent to the base are congruent, thus

$\angle CBA=\angle CAB=25^{\circ}$

The sum of the measures of all interior angles in triangle is always 180°, so

$\angle CAB+\angle CBA+\angle ACB=180^{\circ}\\ \\25^{\circ}+25^{\circ}+\angle ACB=180^{\circ}\\ \\\angle ACB=130^{\circ}$

Angle ACB is central angle subtended on the minor arc AB, angle APB is inscribed angle subtended on the same minor arc AB. The measure of inscribed angle is half the measure of central angle subtended on the same arc, so

$x=\angle APB=\dfrac{1}{2}\cdot 130^{\circ}=65^{\circ}$

8 0

3 years ago

Find the distance between two points -9,-5 and 0,7

Arada [10]

To find the distance, you need to subtract the second point from the first one. So:

0 - (-9) = 9 ( two minuses turn into a positive)

And

7 - (-5) = 12

So the difference between the points is 9 units on the x- axis and 12 on the y-axis.

Hope this helped and pls mark as brainliest!

~Luna

3 0

3 years ago

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