Answer:
c
Step-by-step explanation:
the normal equation is 120 and c is 120
C. $122.10
20 first hour
20+0.1*20 = 22 second hour
22+0.1*22 = 24.2 third hour
24.2+0.1*24.2 = 26.62 fourth hour
26.62+0.1*26.62 = 29.282 fifth hour
Total=$122.10
Answer: It will take 7 days to use the inventory of shipping labels.
Step-by-step explanation:
Given : Total boxes shipped by warehouse worker per day = 25
Every box contains 3 shipping labels.
Inventory has 500 shipping labels.
Then, the total number of boxes can be made = (Total shipping labels) ÷ (labels in each box)
500 ÷ 3 =166.67≈166
Number of days it will take to use the inventory of shipping labels= (total number of boxes can be made) ÷ (Total boxes shipped per day)
= 166÷ 25=6.64≈7
Hence, it will take 7 days to use the inventory of shipping labels.
First, square both sides. This will cancel out the radical.
(a^2 = b + 6)
Then subtract 6 from both sides
b = a^2 - 6
Answer:
Step-by-step explanation:
From the given information,
Suppose
X represents the Desktop computer
Y represents the DVD Player
Z represents the Two Cars
Given that:
n(X)=275
n(Y)=455
n(Z)=405
n(XUY)=145
n(YUZ)=195
n(XUZ)=110
n((XUYUZ))=265
n(X ∩ Y ∩ Z) = 1000-265
n(X ∩ Y ∩ Z) = 735
n(X ∪ Y) = n(X)+n(Y)−n(X ∩ Y)
145 = 275+455 - n(X ∩ Y)
n(X ∩ Y) = 585
n(Y ∪ Z) = n(Y) + n(Z) − n(Y ∩ Z)
195 = 455+405-n(Y ∩ Z)
n(Y ∩ Z) = 665
n(X ∪ Z) = n(X) + n(Z) − n(X ∩ Z)
110 = 275+405-n(X ∩ Z)
n(X ∩ Z) = 570
a. n(X ∪ Y ∪ Z) = n(X) + n(Y) + n(Z) − n(X ∩ Y) − n(Y ∩ Z) − n(X ∩ Z) + n(X ∩ Y ∩ Z)
n(X ∪ Y ∪ Z) = 275+455+405-585-665-570+735
n(X ∪ Y ∪ Z) = 50
c. n(X ∪ Y ∪ C') = n(X ∪ Y)-n(X ∪ Y ∪ Z)
n(X ∪ Y ∪ C') = 145-50
n(X ∪ Y ∪ C') = 95
