F(x)=x²-3x-2 then f(-1) is given by
1 answer:
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Answer:
The probability that the customer is charged incorrectly on at most 2 items is 3.979 × 10⁻².
Step-by-step explanation:
To solve the question, we note that we proceed with the binomial distribution formula as follows
Number of times the customer is incorrectly charged out of ever 10 items = 4
Therefore, the probability that the customer is incorrectly charged is 4/10 = 0.4
That is p(incorrect) = 0.4
Then the probability that the customer is charged incorrectly on at most 2 items is
P(x≤2) = P(x=0) + P(x=1) + P(x=2)
= ₙC ×
×
=
P(x=0) = ₁₄C₀ ×0.4⁰× 0.6¹⁴ = 7.836 × 10⁻⁴
P(x=1) = ₁₄C₁ ×0.4¹× 0.6¹³ = 7.314 × 10⁻³
P(x=2) = ₁₄C₂ ×0.4²× 0.6¹² = 3.169 × 10⁻²
∴ P(x≤2) = 7.836 × 10⁻⁴ + 7.314 × 10⁻³ + 3.169 × 10⁻² = 3.979 × 10⁻²
P(x≤2) = 3.979 × 10⁻².
The probability for choosing green and red is
<u>Solution:</u>
Given that , A bag contains 1 red, 1 yellow, 1 blue, and 1 green marble.
We have to find what is the probability of choosing a green marble, not replacing it, and then choosing a red marble?
Now, we know that,
So, total possible outcomes = 1 red + 1 yellow + 1 blue + 1 green = 4
And now, total outcomes will be only 3 as we are not replacing the picked marble.
Hence, the probability for choosing green and red is