Answer:
The acceleration is exactly 40 mi/h² as shown
Explanation:
Given;
initial velocity of the car, u = 30 mi/h
final velocity of the car, v = 50 mi/h
change in velocity, ΔV = v - u
ΔV = 50 mi/h - 30 mi/h = 20 mi/h
initial time, t₁ = 2:00 PM
final time, t₂ = 2:30 PM
Change in time, Δt = t₂ - t₁
Δt = 2: 30 - 2:00 = 30 mins = 0.5 hour
Acceleration is given as change in velocity per change in time;
a = ΔV / Δt
Therefore, the acceleration is exactly 40 mi/h² as shown.
Answer:
Explanation:
Additional information:
<em>The ball has charge </em><em>, and the ring has positive charge </em>
<em> distributed uniformly along its circumference. </em>
The electric field at distance along the z-axis due to the charged ring is
Therefore, the force on the ball with charge is
and according to Newton's second law
substituting we get:
rearranging we get:
Now we use the approximation that
<em>(we use this approximation instead of the original </em>
<em> since </em>
<em>, our assumption still holds )</em>
and get
Now the last equation looks like a Simple Harmonic Equation
where
is the frequency of oscillation. Applying this to our equation we get:
