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neonofarm [45]
3 years ago
12

What is the speed of a car that traveled 300 miles in 6 hours?

Physics
1 answer:
Misha Larkins [42]3 years ago
7 0

Answer:

50

Explanation:

300 divided by 6

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In the process of electricity, what flows through the wires?
MAVERICK [17]
I think the answer would be
C.Electrons
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t's Peggy Sue's birthday and she's about to blow out the candles on her cake. Brother Roger stops the party when he shouts: "Loo
Ket [755]

Answer:

D) Roger is incorrect. Only a chemical change is taking place as evidenced by the light and heat of the burning candles.

Explanation:

- A physical change is a change in which there is no formation of new substances. Examples of physical changes are the melting or the evaporation of a substance (all phase transitions are examples of physical changes): in such cases, there is no formation of new substances.

- A chemical change is a change in which new substances form. Examples of chemical changes are the chemical reactions: for instance, when a candle burns, a reaction is taken place (oxygen is burnt, transforming into carbon dioxide + heat + light, so this is an example of chemical change).

Therefore, the correct answer is

D) Roger is incorrect. Only a chemical change is taking place as evidenced by the light and heat of the burning candles.

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Can anyone help meee plzzz
hichkok12 [17]

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the first one is higher

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i d k what the second one is

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The 6th harmonic of a pipe is open at both ends has a frequency of 732 Hz, on a day when the temperature is 10 degrees Celsius.
Stels [109]

Answer:

안녕하세요 우리는 어떻게 응을 하루?

Explanation:

이봐 우리는 오늘 응

4 0
3 years ago
Replacing an object attached to a spring with an object having 14 the original mass will change the frequency of oscillation of
Pachacha [2.7K]

Answer:

<em>The frequency changes by a factor of  0.27.</em>

<em></em>

Explanation:

The frequency of an object with mass m attached to a spring is given as

f = \frac{1}{2\pi } \sqrt{\frac{k}{m} }

where f is the frequency

k is the spring constant of the spring

m is the mass of the substance on the spring.

If the mass of the system is increased by 14 means the new frequency becomes

f_{n} = \frac{1}{2\pi } \sqrt{\frac{k}{14m} }

simplifying, we have

f_{n} = \frac{1}{2\pi \sqrt{14} } \sqrt{\frac{k}{m} }

f_{n} = \frac{1}{3.742*2\pi  } \sqrt{\frac{k}{m} }

if we divide this final frequency by the original frequency, we'll have

==> \frac{1}{3.742*2\pi  } \sqrt{\frac{k}{m} }  ÷  \frac{1}{2\pi } \sqrt{\frac{k}{m} }

==> \frac{1}{3.742*2\pi  } \sqrt{\frac{k}{m} }  x  2\pi \sqrt{\frac{m}{k} }

==> 1/3.742 = <em>0.27</em>

7 0
3 years ago
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