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neonofarm [45]
3 years ago
12

What is the speed of a car that traveled 300 miles in 6 hours?

Physics
1 answer:
Misha Larkins [42]3 years ago
7 0

Answer:

50

Explanation:

300 divided by 6

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adelina 88 [10]
Your stomach, as in JUST your stomach?
Well the role of your stomach is to break down large clumps of food. Without that it would be very hard to impossible to digest food.<span />
7 0
3 years ago
The kinetic energy of a book on a shelf is equal to the work done to lift the book to the shelf. t/f
Svet_ta [14]
The kinetic energy of a book on a shelf is equal to the work done to lift the book to the shelf is false. The kinetic energy on the shelf is zero because it is not in action.
7 0
3 years ago
Read 2 more answers
A heat pump absorbs heat from the atmosphere at a rate of 30 kW. If work is being done to run this heat pump at a rate of 7.7 kW
Volgvan

Answer:

Option D 3.9

Explanation:

First, you need to use the correct equation which is the following:

COP = Q/W

Where:

Q = heat absorbed

W = work done by the pump

COP = coefficient of perfomance

We have all the data, so, all you need to do is replace in the above expression and you shoould get the correct result:

COP = 30 / 7.7

COP = 3.896

This result you can round it to 3.9. option D.

8 0
3 years ago
You take the same 3 kg metal block and slide it along the floor, where the coefficient of friction is only 0.4. You release the
spin [16.1K]

Answer:

1.52905 seconds

4.58715 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

\mu = Coefficient of friction = 0.4

g = Acceleration due to gravity = 9.81 m/s²

a = Acceleration = \mu g

Equation of motion

v=u+at\\\Rightarrow t=\frac{v-u}{\mu g}\\\Rightarrow t=\frac{0-6}{-0.4\times 9.81}\\\Rightarrow t=1.52905\ s

It will take 1.52905 seconds for the block to slow down

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2\mu g}\\\Rightarrow s=\frac{0^2-6^2}{2\times 0.4\times -9.81}\\\Rightarrow s=4.58715\ m

The block will travel 4.58715 m before it stops

7 0
3 years ago
What mass of steam at 100°C must be mixed with 119 g of ice at its melting point, in a thermally insulated container, to produce
N76 [4]

Answer:M=27.92\ gm

Explanation:

Given

mass of ice m=119\ gm

Final temperature of liquid T_f=57^{\circ}C

Specific heat of water c=4186\ J/kg-K

Latent heat of fusion L=333\ kJ/kg

Latent heat of vaporization L_v=2256\ kJ/kg

Suppose M is the mass of steam at 100^{\circ} C

Heat required to melt ice and convert it to water at 57^{\circ}C

Q_1=mL+mc(T_f-0)

Heat released by steam

Q_2=ML_v+Mc(100-T_f)

Q_1 and Q_2 must be equal as the heat gained by ice is equal to Heat released by steam

Q_1=Q_2

\Rightarrow mL+mc(T_f-0)= ML_v+Mc(100-T_f)

\Rightarrow M=\dfrac{m[L+c\times T_f]}{L_v+c(100-T_f)}

\Rightarrow M=\dfrac{119[333\times 10^3+4186\times 57]}{2256\times 10^3+4186\times (100-57)}

\Rightarrow M=119\times 0.2346

M=27.92\ gm

7 0
3 years ago
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