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3 years ago

14

what kind of weather is associated with high pressure?How does density,humidity, and air motion compare to that low pressure sys

tem?

1 answer:

frutty [35]3 years ago

6 0

Usually nice weather , i dont know the answer to the second part

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A cyclotron designed to accelerate protons has a magnetic field of magnitude 0.15 T over a region of radius 7.4 m. The charge on

klio [65]

Explanation:

It is given that,

Magnetic field, B = 0.15 T

Charge on a proton, $q=1.60218\times 10^{-19}\ C$

Mass of a proton, $m=1.67262 \times 10^{-27}\ kg$

The cyclotron frequency is given by :

$f=\dfrac{qB}{2\pi m}$

$f=\dfrac{1.60218\times 10^{-19}\ C\times 0.15\ T}{2\pi \times 1.67262 \times 10^{-27}\ kg}$

f = 2286785.40 Hz

or

$\omega=14368296.44\ rad/s$

$\omega=1.43\times 10^7 rad/s$

Hence, this is the required solution.

8 0

3 years ago

Tyrone, an 85-kg teenager, runs off the end of a horizontal pier and lands on a free-floating 130-kg raft that was initially at

Ghella [55]

Answer:u=4.04 m/s

Explanation:

Given

Mass m=85 kg

mass of Raft M=130 kg

velocity of raft and man v=1.6 m/s

Let initial speed of Tyrone is u

Conserving Momentum as there is no external Force

$mu=(M+m)v$

$85\times u=(85+130)\cdot 1.6$

$u=\frac{215}{85}\cdot 1.6$

$u=2.529\cdot 1.6=4.04 m/s$

4 0

3 years ago

What net force would be needed to accelerate the box at 2.3 m/s^2

Akimi4 [234]

The pertinent equation here is F=ma. You haven't shared the mass of the box, so I will use M to represent that mass.

Then F = M(<span>2.3 m/s^2) (answer)</span>

6 0

3 years ago

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The planet Mars has much less gravitational force that Earth. What would happen if you went to Mars?

vovangra [49]

gravitational force of planet exerted on its object near the surface is known as weight

so here we know that gravitational force of mars is much less than the gravitational force of Earth

So on the surface of mars the Weight of objects must be much less than the weight of object on surface of Earth

so here correct answer must be

<em>D. Your weight would decrease.</em>

6 0

3 years ago

An object is located 51 millimeters from a diverging lens. The object has a height of 13 millimeters and the image height is 3.5

12345 [234]

You would get 13.7
mi/51mm=3.5mm/13mm
by solving it you will B13.7mm

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3 years ago

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