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3 years ago

A light wave encounters a partial physical barrier, such as a wall with a hole in it. What is MOST LIKELY to occur?

2 answers:

8 0

The light will be diffracted.
diffraction - bending of a wave in a homogeneous medium around obstacles or through a narrow opening.

hope this helps :)

tatiyna3 years ago

5 0

Most likely, the light wave will be absorbed by the wall. Without any information as to the size and color of the wall, the location and size of the hole, or the location of the light wave, this is a generalized probability problem. For all of the places the light could be, it's more likely that it hits the wall than the hole (if the hole is less than 50% of the area of the wall).

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In an experiment to estimate the acceleration due to gravity, a student drops a ball at a distance of 1 m above the floor. His l

anyanavicka [17]

Answer:

$9.45179\ m/s^2$

$s=4.725895t^2$

Explanation:

t = Time taken = 0.46

u = Initial velocity

v = Final velocity

s = Displacement = 1 m

a = Acceleration

$s=ut+\frac{1}{2}at^2\\\Rightarrow 1=0\times 0.46+\frac{1}{2}\times a\times 0.46^2\\\Rightarrow a=\frac{1\times 2}{0.46^2}\\\Rightarrow a=9.45179\ m/s^2$

The acceleration due to gravity is 9.45179 m/s²

$s=ut+\frac{1}{2}at^2\\\Rightarrow s=\frac{1}{2}at^2\\\Rightarrow s=\dfrac{1}{2}9.45179t^2\\\Rightarrow s=4.725895t^2$

The function is $s=4.725895t^2$

3 0

3 years ago

Calculate the potential required to push eleven amperes through a 20 ohm resistance

den301095 [7]

Answer:

The answer is 220

Explanation:

Volts = current × resistance

Current = 11

Resistance = 20

Volts = 11 × 20

= 220

5 0

3 years ago

Read 2 more answers

Two boxes sit side by side on a smooth horizontal surface. The lighter box 5.2 kg, the heavier box has a mass of 7.4kg (a) find

Paladinen [302]

OK. So you're pushing on the small box, and on the other side of it, the small
box is pushing on the big box. So you're actually pushing both of them.

-- The total mass that you're pushing is (5.2 + 7.4) = 12.6 kg.

-- You're pushing it with 5.0N of force.

-- Acceleration of the whole thing = (force)/(mass) = 5/12.6 = 0.397 m/s² (rounded)

-- Both boxes accelerate at the same rate. So the box farther away from you ...
the big one, with 7.4 kg of mass, accelerates at the same rate.

The force on it to make it accelerate is (mass) x (acceleration) =

(7.4 kg) x (5/12.6 m/s²) = 2.936 N.

The only force on the big box comes from the small box, pushing it from behind.
So that same 2.936N must be the contact force between the boxes.

8 0

3 years ago

What is the x component of (+3m)ι^ And (+3m/s) i^?

expeople1 [14]

The "i" component of a vector is in the x-direction. Therefore, the x-component is 3 m/s.

4 0

3 years ago

Can someone tell me what my displacement is?

natulia [17]

60017 is or answer ok you got it

3 0

3 years ago