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3 years ago

3Mg^3(PO^4)^2 ——— how many atoms are there

Chemistry

1 answer:

AfilCa [17]3 years ago

7 0

36 atoms

Explanation:

Compound:

3 Mg³⁺ (PO₄)²⁻

The compound is 3Mg₂(PO₄)₃

An atom is the smallest indivisible particle of a substance

Elements are atoms that are different from one another.

A compounds is combination of elements to give a distinct matter.

3Mg₂(PO₄)₃

Elements here are Mg, P and O

Atoms:

2 Mg

2 P

8 O

This gives 12 atoms in all

since we have 3mole of the compound, number of atoms = 3 x 12 = 36atoms

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Atoms brainly.com/question/10216585

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An inhibitor is added to an enzyme-catalyzed reaction at a concentration of 26.7 μM. The Vmax remains constant at 50.0 μM/s, but

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Using the Michaelis-Menten equation competitive inhibition, the Inhibition constant, Ki of the inhibitor is 53.4 μM.

<h3>What is the Ki for the inhibitor?</h3>

The Ki of an inhibitor is known as the inhibition constant.

The inhibition is a competitive inhibition as the Vmax is unchanged but Km changes.

Using the Michaelis-Menten equation for inhibition:

Kma = Km/(1 + [I]/Ki)

Making Ki subject of the formula:

Ki = [I]/{(Kma/Km) - 1}

where:

Kma is the apparent Km due to inhibitor
Km is the Km of the enzyme-catalyzed reaction
[I] is the concentration of the inhibitor

Solving for Ki:

where

[I] = 26.7 μM

Km = 1.0

Kma = (150% × 1 ) + 1 = 2.5

Ki = 26.7 μM/{(2.5/1) - 1)

Ki = 53.4 μM

Therefore, the Inhibition constant, Ki of the inhibitor is 53.4 μM.

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2 years ago

Compare natural selection to evolution. Be sure to justify your response in two or more complete sentences.

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3 years ago

What is a possible cause of a large percentage of error in an experiment where mgo is produced from the combustion of magnesium?

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2 years ago

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A container of argon with a volume of 22 ml has a pressure of 101.0 kPa.

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Answer:

The new pressure is 44.4 kPa.

Explanation:

We have,

Initial volume, $V_1=22\ ml$

Initial pressure, $P_1= 101.0\ kPa$

It is required to find the new pressure when the volume is increased to 50 ml. The relationship between pressure and volume is known as Boyle's law.

$PV=k\\\\P_1V_1=P_2V_2$

$P_2$ is final pressure

$P_2=\dfrac{P_1V_1}{V_2}\\\\P_2=\dfrac{22\times 101\times 10^3}{50}\\\\P_2=44440\ Pa\\\\P_2=44.4\ kPa$

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2 years ago

Glucose, C6H12O6,C6H12O6, is used as an energy source by the human body. The overall reaction in the body is described by the eq

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Answer:

Mass of oxygen = 61.824 g

Mass of carbon dioxide = 85.01 g

Explanation:

Given data:

Mass of glucose = 58 g

Mass of carbon dioxide = ?

Mass of oxygen = ?

Solution:

First of all we will write the balanced chemical equation,

C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O

Moles of glucose:

Number of moles = mass / molar mass

Number of moles = 58 g/180 g/mol

Number of moles = 0.322 mol

Now we compare the moles of oxygen with glucose from balance chemical equation.

C₆H₁₂O₆ : O₂

1 : 6

0.322 : 0.322×6 = 1.932 mol

Mass of oxygen:

Mass of oxygen = number of moles × molar mass

Mass of oxygen = 1.932 mol × 32 g/mol

Mass of oxygen = 61.824 g

Now we compare the moles of carbon dioxide with moles of glucose and oxygen.

C₆H₁₂O₆ : CO₂

1 : 6

0.322 : 0.322×6 = 1.932 mol

O₂ : CO₂

6 : 6

1.932 : 1.932

Mass of carbon dioxide;

mass of carbon dioxide = number of moles × molar mass

mass of carbon dioxide = 1.932 mol × 44 g/mol

mass of carbon dioxide = 85.01 g

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