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3 years ago

3Mg^3(PO^4)^2 ——— how many atoms are there

Chemistry

1 answer:

AfilCa [17]3 years ago

7 0

36 atoms

Explanation:

Compound:

3 Mg³⁺ (PO₄)²⁻

The compound is 3Mg₂(PO₄)₃

An atom is the smallest indivisible particle of a substance

Elements are atoms that are different from one another.

A compounds is combination of elements to give a distinct matter.

3Mg₂(PO₄)₃

Elements here are Mg, P and O

Atoms:

2 Mg

2 P

8 O

This gives 12 atoms in all

since we have 3mole of the compound, number of atoms = 3 x 12 = 36atoms

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Atoms brainly.com/question/10216585

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2 years ago

An aqueous CsCl solution is 8.00 wt% CsCl and has a density of 1.0643 g/mL at 20°C. What is the boiling point of this solution?

umka2103 [35]

<u>Answer:</u> The boiling point of solution is 100.53

<u>Explanation:</u>

We are given:

8.00 wt % of CsCl

This means that 8.00 grams of CsCl is present in 100 grams of solution

Mass of solvent = (100 - 8) g = 92 grams

The equation used to calculate elevation in boiling point follows:

$\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of pure solution}$

To calculate the elevation in boiling point, we use the equation:

$\Delta T_b=iK_bm$

Or,

$\text{Boiling point of solution}-\text{Boiling point of pure solution}=i\times K_b\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

where,

Boiling point of pure solution = 100°C

i = Vant hoff factor = 2 (For CsCl)

$K_b$ = molal boiling point elevation constant = 0.51°C/m

$m_{solute}$ = Given mass of solute (CsCl) = 8.00 g

$M_{solute}$ = Molar mass of solute (CsCl) = 168.4 g/mol

$W_{solvent}$ = Mass of solvent (water) = 92 g

Putting values in above equation, we get:

$\text{Boiling point of solution}-100=2\times 0.51^oC/m\times \frac{8.00\times 1000}{168.4g/mol\times 92}\\\\\text{Boiling point of solution}=100.53^oC$

Hence, the boiling point of solution is 100.53

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3 years ago