Usually the presence of a dominant version of allele masks the expression of a recessive allele. A recessive allele is only phenotype is only expressed when 2 recessive alleles combine.
The neutralization reaction goes according to the scheme
H⁺ + OH⁻ = H₂O
acid and base react, salt and water are formed
NaOH + HNO₃ = NaNO₃ + H₂O
2KOH + H₂SO₄ = K₂SO₄ + 2H₂O
So the problem ask to justify that does the result of the calculation justify the original assumptions that all of the SCN is the form of FeNCS^2 and the best way to prove it is that both of them has a relative measurement percentage of 37.681%. I hope this helps
Answer is: <span> mole ratio of heptane vapor to octane vapor is </span>2,8 : 1.
p(C₇H₁₆) = 31 torr.
p(C₈H₁₈) = 11 torr.
x(C₇H₁₆) = 0,5.
x(C₈H₁₈) = 0,5.
p total = (x(C₇H₁₆) · p(C₇H₁₆)) + (x(C₈H₁₈) · p(C₈H₁₈)) = 0,5· 31 torr + 0,5·11 torr = 21 torr.
The mole fraction of heptane in the vapor is:
p(C₇H₁₆) ÷ p total) = 15,5 torr ÷<span> 21 torr = 0,74. </span>
<span>The mole fraction of octane in the vapor is:
</span>p(C₈H₁₈) ÷ p total = 5.5 torr ÷ 21 torr = 0,26.
Mole ratio heptane vapor ÷ octane vapor:
0,74 ÷ 0,26 = 2,8.
Two products: 1-butane and 2-butane.
