The approximate mass of the spherical weight is 51 pounds
To answer the question, we need to know what the mass of the sphere is
<h3>Mass of the sphere</h3>
The mass of the sphere m = ρV where
- ρ = density of steel = 0.284 lb/in³ and
- V = volume of sphere = 4πr³/3 where
- r = radius of sphere = 3.5 in
So, m = ρV
= ρ4πr³/3
Substituting the values of the variables into the equation, we have
m = ρ4πr³/3
= 0.284 lb/in³ × 4π(3.5 in)³/3
= 0.284 lb/in³ × 4π × 42.875 in³/3
= 48.706π lb/3
= 153.014 lb/3
= 51 lb
The approximate mass of the spherical weight is 51 pounds
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It would be: 3(x + 21) ≤ -26
3x + 21 ≤ -26
3x ≤ -47
x < -47/3
In short, Your Answer would be -47/3 or 15.67
Hope this helps!
You would have 1818 of pie left over...... I do not know the fraction of it
Answer:
the larger number is 69
the smaller number is 16
Step-by-step explanation:
x is the smaller number
y is the larger number
x + y = 85
y - 4x = 5
y = 5 + 4x
x + 5 + 4x = 85
5x = 80
x = 16
y = 69
Slope: the tilt. it equals rise over run. so 1/2
