.265
Decimals are ALWAYS tenths, hundredths, then thousandths.
So in this case the 2 will be in the tenths place
the 6 will be in the hundredths place
the 5 will be in the thousandths place.
Answer:
4.8 lbs
Step-by-step explanation:
Candied pecan price: $14.00
Candied Cashew price: $10.00
Mixture price: $12.50
Candied cashew weight: x lbs
Candied pecan weight: 8 lbs
Mixture weight: y pounds
The sum of the weights of candied pecan and candied cashew must equal the weight of the mixture. While the mixture weight multiplied by the mixture price must equal the sum of each individual candy's weight multiplied by its price:
Multiplying the firs equation by -10 and adding it to the second one, gives us the value of "y" which can then be used to find "x":
Therefore, the grocer would need 4.8 pounds of candy cashews to make the mixture.
X=25 is the answer
EXPLANATION:
Since we have here similar triangles, then 2x+2/x+3 must be equivalent of 26/14
2x+2/x+3=26/14
2x+2/x+3=13/7
7(2x+2)=13(x+3)
14x+14=13x+39
x=25
Step-by-step explanation:
Percentage increase = (279 - 180)/180 x 100% = 55%
this is a topic on percentage. the above question requires a use of a kind of formula if you wish to explore more into this topic you can give me a follow on Instagram (learntionary) I've already posted some notes on this topic and will be doing more on others and also I'll be providing tips on some topics as well!
<span>6x^2 - 24x^3 + 36x becomes easier to factor if you notice that 6x is a factor of all 3 terms. Factoring, we get 6x(x - 4x^2 + 6), or -6x(4x^2 - x + 6).
To factor </span>4x^2 - x + 6, I'd choose from one of the following approaches: quadratic formula, factoring using synthetic division.
<span>
Quadratic formula:
1 plus or minus sqrt( 1 - 4(4)(6) )
x = -----------------------------------------------
8
1 plus or minus sqrt(-95)
= ------------------------------------
8
Then the desired factors are complex:
(6) (x - [1 plus sqrt(95] ) (x - [1 minus sqrt(95) ] )
-----------------------------------------------------------------
8
</span>