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IrinaVladis [17]
3 years ago
10

If a car travels 40 km/hr for hours how far has it traveled

Physics
1 answer:
Rainbow [258]3 years ago
8 0
It depends on how many hours!
1 hour = 40km
2 hours = 80km
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A mass weighing 14 pounds stretches a spring 2 feet. The mass is attached to a dashpot device that offers a damping force numeri
Elodia [21]

Answer:

The motion is over-damped when λ^2 - w^2 > 0 or when b^{2} > 0.86

The motion is critically when λ^2 - w^2 = 0 or when b^{2} = 0.86

The motion is under-damped when λ^2 - w^2 < 0 or when b^{2} < 0.86

Explanation:

Using the newton second law

k is the spring constante

b positive damping constant

m mass attached

m\frac{d^{2} x}{dt^{2}} = - kx - b\frac{dx}{dt}

x(t) is the displacement from the equilibrium position

\frac{d^{2} x}{dt^{2}} +\frac{b}{m}\frac{dx}{dt} + \frac{k}{m}x = 0

Converting units of weights in units of mass (equation of motion)

m = \frac{W}{g} = \frac{14}{32} = 0.43 slug

From hook's law we can calculate the spring constant k

k = \frac{W}{s} = \frac{14}{2} = 7 lb/ft

If we put m and k into the DE, we get

\frac{d^{2} x}{dt^{2}} +\frac{b}{0.43}\frac{dx}{dt} + 16.28x = 0

Denoting the constants

2λ = \frac{b}{m} = \frac{b}{0.43}

λ = b/0.215

w^{2} = \frac{k}{m} = 16.28

λ^2 - w^2 = \frac{b^{2} }{0.046} - 16.28

This way,

The motion is over-damped when λ^2 - w^2 > 0 or when b^{2} > 0.86

The motion is critically when λ^2 - w^2 = 0 or when b^{2} = 0.86

The motion is under-damped when λ^2 - w^2 < 0 or when b^{2} < 0.86

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Write down the boiling point and freezing point of mercury an alcohol​
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Describe your motion in terms of velocity and acceleration as you ride in a car down the street, come to a red light, wait for t
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7 0
3 years ago
Read 2 more answers
. An 1800-W toaster, a 1400-W electric frying pan, and a 75-W lamp are plugged into the same outlet in a 15-A, 120-V circuit. (T
s2008m [1.1K]

Answer:

Explanation:

The devices are connected in parallel, the same voltage will flow through them

1) I, current in the 1800 W toaster

P, power = I V

where p = 1800 W

1800 /120 = I

I drawn by the toaster = 15 A

2) I, current drawn by the 1400 W frying pan = 1400 / 120 = 11.667 A

3) I, current drawn by 75 W = 75 / 120 = 0.625 A

B) Total current drawn by the circuit = 15 A + 11.667 A + 0.625 A = 27.292 A which is greater than 15-A hence the combination will blow the fuse

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Read 2 more answers
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