All categories

4 years ago

What happens to a light ray passing through the center of a lens?

Physics

2 answers:

lara31 [8.8K]4 years ago

7 0

What happens when a light ray passes through the focal point, and then reflects off of a convex mirror?

The reflected ray will run parallel to the center of curvature.

The reflected ray will run parallel to the principal axis.

The reflected ray will pass through the center of curvature.

The reflected ray will pass through a point between the center of curvature and the focal point.

The reflected ray will pass through a point between the focal point and the vertex.

Is it out of these choices?

Readme [11.4K]4 years ago

6 0

Theoretically, the light ray will not change direction. The center of a lens is called the optical center. If the ray of light hits the lens even just a little bit off center, the light ray is refracted. Refraction happens when the incident and exit angles of the ray are different. The optical center is guaranteed to not have any difference in angle, which allows the light ray to pass through directly without changing direction.

You might be interested in

g If the interaction of a particle with its environment restricts the particle to a finite region of space, the result is the qu

Travka [436]

Answer:

the result is the quantization of __Energy__ of the particle

Explanation:

3 0

4 years ago

The Shinkansen (bullet train in Japan) makes a trip from Tokyo Station to Kyoto station in 2 hours and 14 min. The distance trav

11Alexandr11 [23.1K]

Answer:

v = 57.2 m/s

Explanation:

The average velocity of the train can be defined as the total distance covered by the train divided by the time taken by the train to cover that distance. Therefore, we will use the following formula to find the average velocity of the train:

v = s/t

where,

s = distance covered = 460 km = (460 km)(1000 m/1 km) = 4.6 x 10⁵ m

t = time taken to cover the distance = 2 h 14 min

Now, we convert it into minutes:

t = (2 h)(60 min/1 h) + 14 min

t = 120 min + 14 min = (134 min)(60 s/1 min)

t = 8040 s

Therefore, the value of velocity will be:

v = (4.6 x 10⁵ m)/8040 s

7 0

3 years ago

Two charges are separated by a distance 'd' and exert a mutual attractive force of 'f' on each other. if the distance is decreas

Zepler [3.9K]

Peanut butter an jelly crackers are the best

5 0

4 years ago

The equation that relates two poles to the force between them and their separation is the ____ square law.

Ivenika [448]

A-exponential
You welcome

4 0

3 years ago

What happens if :<br> . The test charge is not tiny.

docker41 [41]

The magnitude of the test charge must be small enough so that it does not disturb the issuance of the charges whose electric field we wish to measure otherwise the metric field will be different from the actual field.

<h3>How does test charge affect electric field?</h3>

As the quantity of authority on the test charge (q) is increased, the force exerted on it is improved by the same factor. Thus, the ratio of force per charge (F / q) stays the same.

Adjusting the amount of charge on the test charge will not change the electric field force.

<h3>What is a test charge used for?</h3>

The charge that is used to measure the electric field strength is directed to as a test charge since it is used to test the field strength. The test charge has a portion of charge denoted by the symbol q.

To learn more about test charge, refer

brainly.com/question/16737526

#SPJ9

3 0

2 years ago