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Salsk061 [2.6K]
3 years ago
13

What happens to a light ray passing through the center of a lens?

Physics
2 answers:
lara31 [8.8K]3 years ago
7 0

What happens when a light ray passes through the focal point, and then reflects off of a convex mirror?

A.  

The reflected ray will run parallel to the center of curvature.

B.  

The reflected ray will run parallel to the principal axis.

C.  

The reflected ray will pass through the center of curvature.

D.  

The reflected ray will pass through a point between the center of curvature and the focal point.

E.  

The reflected ray will pass through a point between the focal point and the vertex.

Is it out of these choices?

Readme [11.4K]3 years ago
6 0
Theoretically, the light ray will not change direction. The center of a lens is called the optical center. If the ray of light hits the lens even just a little bit off center, the light ray is refracted. Refraction happens when the incident and exit angles of the ray are different. The optical center is guaranteed to not have any difference in angle, which allows the light ray to pass through directly without changing direction.
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A loop of wire is placed in a uniform magnetic field. For what orientation of the loop is the magnetic flux a maximum? For what
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Answer:

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when angle is zero then flux is maximium because when angle zerocos is maximium

8 0
3 years ago
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Masja [62]

Answer:mile

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Why is Einstein's description of gravity called a theory, while Newton's is a law?
Ludmilka [50]
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4 0
3 years ago
Read 2 more answers
For a photoelectric tube, calculate the voltage which will be just sufficient to stop electrons emitted by the sodium photo-plat
Talja [164]

Answer:

1.11 V

Explanation:

Given that the Einstein photoelectric equation states that;

KE = E - Wo

E = energy of incident photon

Wo= work function of the metal

E = hf = 6.64 x 10-34 * 6 x 1014

E = 39.84 * 10^-20 J or 3.98  * 10^-19 J

KE = 3.98  * 10^-19 J - 2.2 x 10-19J

KE = 1.78 *  10^-19J

We convert this value of KE to electron volts

KE = 1.78 *  10^-19J/1.6 x 10-19C

KE = 1.11 eV

Hence; 1.11 V will be just sufficient to stop electrons emitted by the sodium photo-plate reaching the collector plate.

8 0
3 years ago
True or False. In a parallel circuit, the voltage is the same anywhere in the circuit.
FrozenT [24]
True! hope this helps:)
7 0
3 years ago
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