Answer:
tension in the rope is 22.29 N
angle is 56.06 degree
Explanation:
Given data
mass = 1.27 kg
horizontal force = 18.5 N
acceleration = 9.81 m/s2
to find out
magnitude and the rope angle
solution
we know object is in equilibrium so net force is zero here
so net force at x axis = 0 that mean F - Tsinθ = 0 , F = Tsinθ
and net force at y axis = 0 that is T cosθ - mg = 0 , T cosθ = mg
in equilibrium condition
F / mg = Tsinθ / T cosθ
18.5/ 1.27× 9.81 = sinθ / cosθ
so θ = tan^-1 (1.4859)
θ = 56.06 degree
angle is 56.06 degree
so F = Tsinθ
18.5 = T sin(56.06)
T = 18.5 / 0.8296
tension in the rope is 22.29 N
Answer:
α = 3070rev/s^2
θ = 5541.66 revolutions
Explanation:
Given;
Operating angular speed w = 350000 rpm
time t = 1.9s
Angular acceleration = change in angular speed/time
Angular acceleration=350000rpm×1/60 min/sec ÷ 1.9s
Angular acceleration α = 3070rev/s^2
Number of revolutions θ = 1/2 × α × t^2
Since initial angular speed is zero
Substituting the values;
θ = 1/2 × 3070 × 1.9^2
θ = 5541.66 revolutions
Answer:
Explanation:
A combination of two controlled variables will make an experiment the most reliable.
Variables are the values that we take under any circumstance while doing an experiment so that we can keep on changing and get new results at the end.
It is important to have them in pair so that two values can be kept on changing in terms of any constant condition. This will help to get better results in over all experiment data.
Growing quickly
concentrated in a few areas
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