1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Studentka2010 [4]
3 years ago
15

How does the end point differ from the equivalence point of a titration?​

Physics
1 answer:
Gwar [14]3 years ago
3 0

<u>Answer:</u>

<em>Equivalence point and end point are terminologies in pH titrations and they are not the same. </em>

<u>Explanation:</u>

In a <em>titration the substance</em> added slowly to a solution usually through a pippette is called titrante and the solution to which it is added is called titrand. In acid-base titrations acid is added to base or base is added to acid.the strengths of the <em>acid and base titrated</em> determines the nature of the final solution.

At equivalence point the <em>number of moles of the acid</em> will be equal to the number of moles of the base as given in the equation.  The nature of the final solution determines the <em>pH at equivalence point. </em>

<em>A pH less than 7 will be the result if the resultant is acidic and if it is basic the pH will be greater than 7. </em>In a strong base-strong acid and weak base-weak acid titration the pH at the equivalence point will be 7 indicating <em>neutral nature of the solution. </em>

You might be interested in
Tim made tomato soup from scratch. When he cleaned up, he noticed that the aluminum pan was damaged. Analyze what happened to th
mr_godi [17]

Answer:

D) The acidic tomato juice reacted unfavorably with the aluminum pan

5 0
3 years ago
Read 2 more answers
After driving a portion of the route, the taptap is fully loaded with a total of 27 people including the driver, with an average
belka [17]

We will define the Total mass to calculate the force, so our values are:M_p = 69*27=1823Kg\\M_g=15*3=45Kg\\M_c=3*5=15Kg\\M_B=25Kg

Total Mass = 1863+45+15+25=1948Kg

The Weight is,

F=mg=1948*98=19090.4N

Through the hook's Law we calculate X.

F_s=Kx, where x is the lenght of compression and K the Spring constant.

We don't have a K-Spring, but we can assume a random value (or simply let the equation in function of K)

X = \frac{F_s}{x} \\X = \frac{1909.4}{k}

I assume a value of K=4*10^4N/m

X= \frac{1909.4}{4*10^4} = 0.48m

6 0
3 years ago
I need help ASAP I need to get this right plz plz plz!!!!!
Rina8888 [55]

<em><u>The</u></em><em><u> </u></em><em><u>atomic</u></em><em><u> </u></em><em><u>nucleus</u></em><em><u> </u></em><em><u>consists</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>protons</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>neutrons</u></em><em><u>.</u></em>

<em><u>Additional</u></em><em><u> </u></em><em><u>information</u></em><em><u>:</u></em>

<em><u>Protons</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>positive</u></em><em><u>ly</u></em><em><u> </u></em><em><u>charged</u></em><em><u> </u></em><em><u>particl</u></em><em><u>e</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>neutrons</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>negative</u></em><em><u>ly</u></em><em><u> </u></em><em><u>charged</u></em><em><u> </u></em><em><u>particle</u></em><em><u>.</u></em>

<em><u>Hope</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>help</u></em><em><u> </u></em><em><u>u</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>:</u></em><em><u>)</u></em>

3 0
3 years ago
Read 2 more answers
I WILL GIVE BRAILYEST!!! What is the mass of an object moving at a velocity of 5 m/s if the momentum of the object is 50 kg•m/s?
lianna [129]

Answer:

a. 250kg I think it's the right answer. hope it helps:)

7 0
2 years ago
Read 2 more answers
A 40-cmcm-long tube has a 40-cmcm-long insert that can be pulled in and out. A vibrating tuning fork is held next to the tube. A
Licemer1 [7]

Answer:

1070 Hz

Explanation:

First, I should point out there might be a typo in the question or the question has inconsistent values. If the tube is 40 cm long, standing waves cannot be produced at 42.5 cm and 58.5 cm lengths. I assume the length is more than the value in the question then. Under this assumption, we proceed as below:

The insert in the tube creates a closed pipe with one end open and the other closed. For a closed pipe, the difference between successive resonances is a half wavelength \frac{\lambda}{2}.

Hence, we have

\dfrac{\lambda}{2}=58.5-42.5=16 \text{ cm}

\lambda=32\text{ cm}=0.32 \text{ m}.

The speed of a wave is the product of its wavelength and its frequency.

v=f\lambda

f=\dfrac{v}{\lambda}

f=\dfrac{343}{0.32}=1070 \text{ Hz}

7 0
3 years ago
Other questions:
  • Which of the following components of an electrical circuit is a source of voltage?
    10·2 answers
  • n object moves with a constant speed of 30 m/s on a circular track of radius 150 m. What is the acceleration of the object
    14·1 answer
  • Which of the following can be explained with science? A.Plant growth B.Career options C.Moral value D.Meaning of life
    9·2 answers
  • The equation for the speed of a satellite in a circular orbit around the earth depends on mass. Which mass?
    9·1 answer
  • A baseball is hit high and far. Which of the following statements is true? At the highest point,
    6·1 answer
  • What happens to the compass needle as you move the compas<br> around the magnet?
    7·1 answer
  • How to tell how much work gravity does on something?
    7·1 answer
  • you and a friend setup an umbrella and chairs at a beach. your friend goes into the surf zone while you relax on the sand. sever
    14·1 answer
  • Which of the following is closest to 2cm?
    7·1 answer
  • A concrete block (B-36 x10 °C-') of volume 100 mat 40°C is cooled to
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!