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3 years ago

How does the end point differ from the equivalence point of a titration?

Physics

1 answer:

Gwar [14]3 years ago

3 0

Answer:

Equivalence point and end point are terminologies in pH titrations and they are not the same. 

Explanation:

In a titration the substance added slowly to a solution usually through a pippette is called titrante and the solution to which it is added is called titrand. In acid-base titrations acid is added to base or base is added to acid.the strengths of the acid and base titrated determines the nature of the final solution.

At equivalence point the number of moles of the acid will be equal to the number of moles of the base as given in the equation. The nature of the final solution determines the pH at equivalence point. 

A pH less than 7 will be the result if the resultant is acidic and if it is basic the pH will be greater than 7. In a strong base-strong acid and weak base-weak acid titration the pH at the equivalence point will be 7 indicating neutral nature of the solution. 

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What line of code will call force with a value of 10 for mass and a value of 9.81 for acceleration?

Kaylis [27]

Line of code will call force with a value of 10 for mass and a value of 9.81 for acceleration is force(10, 9.81).

<h3 /><h3>Line of code for force and acceleration</h3>

In mechanics, acceleration refers to the rate at which an object's velocity with respect to time varies.
Acceleration is a vector quantity (in that they have magnitude and direction).
The direction of an object's acceleration is determined by the direction of the net force acting on it.
Newton's Second Law states that the combined effect of two factors determines how much an item accelerates.
The size of the net balance of all external forces acting on the object is, in accordance with the materials used to create it.
It inversely proportional to its mass, whereas the magnitude of the net resultant force is directly proportional to the net force.

def force(mass, acceleration):

force_val = mass*acceleration

return force_val

10 is assigned to mass and 9.81 is assigned to acceleration

def force(10, 9.81)

So, Line of code will call force with a value of 10 for mass and a value of 9.81 for acceleration is force(10, 9.81).

Learn more about acceleration here:

brainly.com/question/460763

#SPJ4

7 0

1 year ago

Assume the space shuttle's main engines produce 764,576 newtons of thrust, and the shuttle has a mass of 78,018 kg. Why does the

Nady [450]

Weight of anything = (mass) x (gravity in the place where the thing is)

Weight of anything on Earth = (mass) x (9.81 m/s²)

Weight of the shuttle = (78,018 kg) x (9.81 m/s²)

Weight of the shuttle, on Earth = 765,357 Newtons

Thrust of main engines = 764,576 Newtons

Are you starting to see the problem yet ?

The weight of the whole thing standing on the launch pad is 751 Newtons more than the maximum thrust of the main engines, and the engines can't lift it ! Even with all throttles wide open, the main engines alone would need about 175 more pounds of thrust to budge that load off the ground. Even with the pedal to the metal, with flame and smoke belching out and covering the whole launch complex, the shuttle would just sit there and never leave the pad.

Well, no. That's not exactly what would happen. As the fuel in the main monster fuel tank is burned, the weight decreases. So it would actually happen like this: After the man announced "Zero ! We have ignition ! All engine running !", the ship would just sit there on the pad ... at first. It would go nowhere and not even wiggle, UNTIL the first 175 pounds of fuel got burned without accomplishing anything. The ship would then be 175 pounds lighter. At that point, the weight would be exactly equal to the thrust of the main engines, and the vertical forces on the ship would be balanced. Then, as MORE fuel continued to be wasted and the weight continued to decrease, the main engines could just begin to lift the ship off the pad.

So the correct answer is choice-D . It tells the whole story, quicker than I can tell it.

4 0

3 years ago

A 4.00-kg block hangs by a light string that passes over a massless, frictionless pulley and is connected to a 6.00-kg block tha

Anna007 [38]

Answer:

v = 2.82 m/s

Explanation:

For this exercise we can use the conservation of energy relations.

We place our reference system at the point where block 1 of m₁ = 4 kg

starting point. With the spring compressed

Em₀ = K_e + U₂ = ½ k x² + m₂ g y₂

final point. When block 1 has descended y = - 0.400 m

Em_f = K₂ + U₂ + U₁ = ½ m₂ v² + m₂ g y₂ + m₁ g y

as there is no friction, the energy is conserved

Em₀ = Em_f

½ k x² + m₂ g y₂ = ½ m₂ v² + m₂ g y₂ + m₁ g y

½ k x² - m₁ g y = ½ m₂ v²

v² = $\frac{k}{m_2} x^2 - 2 \frac{m_1}{m_2} \ g y$

let's calculate

v² = $\frac{180}{6.00} \ 0.300^2 - 2 \ \frac{4.00}{6.00} \ 9.8 \ (- 0.400)$

v² = 2.7 + 5.23

v = √7.927

v = 2,815 m / s

using of significant figures

v = 2.82 m/s

5 0

3 years ago

Two satellites A and B of the same mass are orbiting Earth in concentric orbits. The distance of satellite B from Earth’s center

riadik2000 [5.3K]

Answer:

ratio of tangential velocity of satellite b and a will be 0.707

Explanation:

We have given distance of satellite B from satellite A is twice

So $r_b=2r_a$

Tangential speed of the satellite is given by

$v=\sqrt{\frac{GM}{r}}$ , G is gravitational constant. M is mass of satellite and r is distance from the earth

We have to find the ratio of tangential velocities of b and a

From the relation we can see that tangential velocity is inversely proportional to square root of distance from earth

So $\frac{v_b}{v_a}=\sqrt{\frac{r_a}{r_b}}$

$\frac{v_b}{v_a}=\sqrt{\frac{r_a}{2r_a}}$

$\frac{v_b}{v_a}=\sqrt{\frac{1}{2}}$

$\frac{v_b}{v_a}=0.707$

So ratio of tangential velocity of satellite b and a will be 0.707

5 0

3 years ago

Can you please help me? It’s a science question and I really don’t know the answer

Svetllana [295]

Answer:

A. It will continue traveling at the same speed.

Explanation:

I'm not 100% sure on this answer, but if I had this question I would be confident in this answer. It makes sense because unbalanced forces cause an object to start, stop, slow down, or speed up. Without these forces, the object should just keep traveling at the same speed.

I hope this helps! Let me know if it's right or not. ☺

5 0

3 years ago

How does the end point differ from the equivalence point of a titration?​

How does the end point differ from the equivalence point of a titration?