(81^-0.25)^3 = ( 1 / (81^0.25) )^3
<span>81^.025 is the 4th root of 81 which is 3 </span>
<span>Therefor </span>
<span>( 1 / (81^0.25) )^3 = (1/3)^3 </span>
<span>(1/3)^3 = 1/27 <-----
Hope I Helped You!!! :-)
Have A Good Day!!!</span>
Answer:
<em>5</em><em> players participated in the tournament.</em>
Step-by-step explanation:
In a small chess tournament, 20 matches were played.
Let us assume that n number of players participated in the tournament
As in each game 2 players play, so the number of ways they can play is,

As they played 2 games with every other participant in the tournament.
So the total number of games is,

But it is given to be 20, so





As
, so we get n=5.
Therefore, 5 players participated in the tournament.
Answer:
% increase = 200%
Step-by-step explanation:
Answer:
<h2>30% is enrolled out-of-district.</h2>
Step-by-step explanation:
According to the word problem, the number is increased by 50%.
To increase a number by a percent, multiply the number and the percent.
We can do this by changing both percents to decimals.
To change a percent to a decimal, divide it by 100.


The number is INCREASED by 50% so 0.5 would become 1.5.

<h2>0.3 = 30%.</h2>
Answer:
Group A, because seven children have a forearm length longer than 10 inches
Step-by-step explanation:
Create the dot plots based on the given information (please see attached images).
Group A = blue dots
Group B = red dots
From inspection of the attached dot plots, we can see that Group A appears to have the longer average forearm length. This is because 7 children have a forearm length of longer than 10 inches.
To calculate the average forearm length, sum all data values and divide by the total number of data values.


Thus proving that Group A has the longer average former length.