Answer:
b is 10 times greater
Step-by-step explanation:
If we multiply the first ratio by 2/2, we get 2/10. Since b=10 and c=1, b is 10 times greater.
m^2 -11m -60 = 0
m^2 -11m =60
(m^2 -11m + 121/4) = 361/4
(m - 11/2)^2 = 361/4
m - 11/2 = + or - 19/2
m = 11/2 + 19/2, 11/2 - 19/2
m = 15, -4
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m^2 -11m -60
(11 +- Square root (121 +240))/2
11/2 +- 19/2
m= 15, -4
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m^2 -11m -60
(m - 15) (m + 4)
m = 15, -4
14.07, 14 7/10, fourteen and seven tenths
Answer:
z = -10
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
Step-by-step explanation:
<u>Step 1: Define equation</u>
-4 - (z - 6) = 12
<u>Step 2: Solve for </u><em><u>z</u></em>
- Distribute negative: -4 - z + 6 = 12
- Combine like terms: -z + 2 = 12
- Subtract 2 on both sides: -z = 10
- Divide -1 on both sides: z = -10
<u>Step 3: Check</u>
<em>Plug in z to verify it's a solution.</em>
- Substitute: -4 - (-10 - 6) = 12
- Subtract: -4 - (-16) = 12
- Simplify: -4 + 16 = 12
- Add: 12 = 12
Here we see that 12 does indeed equal 12.
∴ z = -10 is a solution of the equation.
Answer:
90.6m
Step-by-step explanation:
Initial speed = 8m/s
Time = 4.3 s
In studying the motion of an object, we often make use of kinematic equation
s = ut + 1/2at^2
v^2 = u^2 + 2as
a = (v - u) / t
v = final velocity
u = initial velocity
s = distance or height
t = time
a = acceleration due to gravity
Given time to hit the ground as 4.3s, we calculate the height by using
s = ut + 1/2at^2
Since the stone is moving against gravity, a is negative
u = 0
s = 0(4.3) +1/2(-9.8)(4.3)^2
s = -90.6m
The height of the cliff is 90.6m
