V = s²h
<span>150 = s²h </span>
<span>150 = s²(3/2)s </span>
<span>(2/3)150 = s³ </span>
<span>100 = s³ </span>
<span>s = ∛100 (approx 4.642 in) </span>
If you call 
the mass of the ant and 
the load, we have the equation
In fact, the mass of the ant is one tenth of the load, which is exactly what this equation states.
Since we are given the load, we simply need to plug its value in the equation to deduce the mass of the ant:
Answer:
Step-by-step explanation:
To get the reasonable range of the situation, we will find the minimum value and maximum value of the calories that can be dressed.
The minimum occur at when x = 0
f(0) = 100(0) +50.
f(0) = 50
Hence the minimum value of the calorie is 50.
The maximum value occur at f'(x)
f'(x) = 100
Hence the maximum value of the calorie is 100
Hence, the reasonable range for the situation is 50 ≤ x ≤ 100
17.8 multiplied by 2 is 35.6
9.5 multiplied by 2 is 19
Now you take both of them and add them together.
35.6 + 19 = 54.6
Your answer should be 54.6 inches of ribbon.
Hope this helps.
17,900 x 0.1296 = 2318.05
2318.05 should be subtracted from 17,900 and it should be somewhere around 15,581.95
