If in the triangle ABC , BF is an angle bisector and ∠ABF=41° then angle m∠BCE=8°.
Given that m∠ABF=41° and BF is an angle bisector.
We are required to find the angle m∠BCE if BF is an angle bisector.
Angle bisector basically divides an angle into two parts.
If BF is an angle bisector then ∠ABF=∠FBC by assuming that the angle is divided into two parts.
In this way ∠ABC=2*∠ABF
∠ABC=2*41
=82°
In ΔECB we got that ∠CEB=90° and ∠ABC=82° and we have to find ∠BCE.
∠BCE+∠CEB+EBC=180 (Sum of all the angles in a triangle is 180°)
∠BCE+90+82=180
∠BCE=180-172
∠BCE=8°
Hence if BF is an angle bisector then angle m∠BCE=8°.
Learn more about angles at brainly.com/question/25716982
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Invert and multiply
2/x*(3/(4x))
Then proceed to simplify
(You must simplify twice might I add)
Answer:
74.32
Step-by-step explanation:
Add the two together, and you have your answer b/c it's asking for the total length of the line
X=1
because you would add two to the other side and have 2x=2 divide by 2 and you would be left with x=1
Answer:
51.7661748226 degrees; 38.2338251774 degrees
Step-by-step explanation:
First, draw a diagram to illustrate this situation. Looking at angle A, Eric's height, 1.65 m, corresponds to OPPOSITE, and Eric's shadow, 1.30 m, corresponds to ADJACENT. Using SOH CAH TOA, the equation is:
tan(A) = 1.65/1.30
A = arctan(1.65/1.30)
A = 51.7661748226 deg
Looking at angle B, 1.65 m is ADJACENT and 1.30 m is OPPOSITE. Therefore, the equation is:
tan(B) = 1.30/1.65
B = arctan(1.30/1.65)
B = 38.2338251774 deg
