W(Cl)=0.3877
w(O)=0.6123
M(Cl)=35.5 g/mol
M(O)=16.0 g/mol
ClₐOₓ
M(ClₐOₓ)=35.5a+16.0x
w(Cl)=35.5a/(35.5a+16.0x)
w(O)=16.0x/(35.5a+16.0x)
solve a system of two equations with two unknowns
35.5a/(35.5a+16.0x)=0.3877
16.0x/(35.5a+16.0x)=0.6123
a=2
x=7
Cl₂O₇ is the empirical formula
Answer:
We need 27.56 moles hydrogen to produce 13.78 mol of ethane. (option 3)
Explanation:
Step 1: Data given
Moles ethane produced = 13.78 moles
Step 2: The balanced equation
C2H2 + 2H2 → C2H6
Step 3: Calculate moles of hydrogen
For 1 mol acetylene (C2H2) we need 2 moles hydrogen (H2) to produce 1 mol of ethane (C2H6)
For 13.78 moles ethane produced we need 2*13.78 = 27.56 moles hydrogen (H2)
We need 27.56 moles hydrogen to produce 13.78 mol of ethane. (option 3)
Answer:
138mL are required to make the solution
Explanation:
A solution of 0.270M contains 0.270 moles of solute (NaCl in this case), per liter of solution.
To solve this problem we need to determine the moles of NaCl in 2.18g. With these moles and molarity we can find the volume required to prepare the solution:
<em>Moles NaCl -Molar mass: 58.44g/mol-:</em>
2.18g * (1mol / 58.44g) = 0.0373moles NaCl
<em>Volume of solution:</em>
0.0373moles NaCl * (1L / 0.270moles) = 0.138L
<h3>138mL are required to make the solution</h3>
Answer:
I think it is E or C
Explanation:
If you multiply E out the result is 530,000,000 which is higher than the rest. If not that than I think it is C, one of the two.
