if you were to fold a piece of paper into a bunch of pieces.
Explanation:
its just a different shape but it's still the same piece of paper
Answer:- Molarity of the acid solution is 0.045M.
Solution:- The balanced equation for the reaction of given acid and base is:
From the balanced equation, they react in 1:1 mol ratio. So, we could easily solve the problem using the equation:
where, 
is the molarity of acid, 
is the molarity of base, 
is the volume of acid and 
is the volume of base.
Let's plug in the given values in the equation:
on rearranging the above equation:
= 0.045M
So, the molarity of the acid solution is 0.045M.
Answer:
A weak acid
Explanation:
Im not sure if its right. But lets see someone else do it.
Answer:
The percent by mass of copper in the mixture was 32%
Explanation:
The ammount of HNO₃ used is:
mol HNO₃ = volume * concentration
mol HNO₃ = 0.015 l * 15.8 mol/l
mol HNO₃ = 0.237 mol
According to the reaction, 4 mol HNO₃ will react with 1 mol Cu and produce 1 mol Cu²⁺. Since we have 0.237 mol HNO₃, the amount of Cu that could react would be (0.237 mol HNO₃ * 1 mol Cu / 4 mol HNO₃) 0.06 mol. This reaction would produce 0.060 mol Cu²⁺, however, only 0.010 mol Cu²⁺ were obtained, indicating that only 0.010 mol Cu were present in the mixture. This means that the acid was in excess, so we can assume that all copper present in the mixture has reacted.
Since 0.010 mol of Cu²⁺ were produced, the amount of Cu was 0.01 mol.
1 mol of Cu has a mass of 63.5 g, then 0.01 mol has a mass of:
0.01 mol Cu * 63.5 g / 1 mol = 0.635 g.
Since this amount was present in 2.00 g mixture, the amount of copper in 100 g of the mixture will be:
100 g(mixture) * 0.635 g Cu / 2 g(mixture) = 32 g
Then, the percent by mass of Cu (which is the mass of Cu in 100 g mixture) is 32%
