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True [87]
3 years ago
12

Anna is following this recipe to make biscuits.

Mathematics
1 answer:
guajiro [1.7K]3 years ago
8 0
125.6=750 so
24biscuits . 6=144
Then60.6=360g sugar
Step-by-step explanation
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What is 3х – 18y = 4
kow [346]

The answer is no solution

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3 years ago
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Hot dogs are sold in packages of 8, and hot dog buns are sold in packages of 12. What's the smallest number of each that could b
PIT_PIT [208]

24 is the answer         8x3 = 24   12x2 = 24           8*3 = 12*2  

7 0
4 years ago
The following results come from two independent random samples taken of two populations.
photoshop1234 [79]

Answer:

(a)\ \bar x_1 - \bar x_2 = 2.0

(b)\ CI =(1.0542,2.9458)

(c)\ CI = (0.8730,2.1270)

Step-by-step explanation:

Given

n_1 = 60     n_2 = 35      

\bar x_1 = 13.6    \bar x_2 = 11.6    

\sigma_1 = 2.1     \sigma_2 = 3

Solving (a): Point estimate of difference of mean

This is calculated as: \bar x_1 - \bar x_2

\bar x_1 - \bar x_2 = 13.6 - 11.6

\bar x_1 - \bar x_2 = 2.0

Solving (b): 90% confidence interval

We have:

c = 90\%

c = 0.90

Confidence level is: 1 - \alpha

1 - \alpha = c

1 - \alpha = 0.90

\alpha = 0.10

Calculate z_{\alpha/2}

z_{\alpha/2} = z_{0.10/2}

z_{\alpha/2} = z_{0.05}

The z score is:

z_{\alpha/2} = z_{0.05} =1.645

The endpoints of the confidence level is:

(\bar x_1 - \bar x_2) \± z_{\alpha/2} * \sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}

2.0 \± 1.645 * \sqrt{\frac{2.1^2}{60}+\frac{3^2}{35}}

2.0 \± 1.645 * \sqrt{\frac{4.41}{60}+\frac{9}{35}}

2.0 \± 1.645 * \sqrt{0.0735+0.2571}

2.0 \± 1.645 * \sqrt{0.3306}

2.0 \± 0.9458

Split

(2.0 - 0.9458) \to (2.0 + 0.9458)

(1.0542) \to (2.9458)

Hence, the 90% confidence interval is:

CI =(1.0542,2.9458)

Solving (c): 95% confidence interval

We have:

c = 95\%

c = 0.95

Confidence level is: 1 - \alpha

1 - \alpha = c

1 - \alpha = 0.95

\alpha = 0.05

Calculate z_{\alpha/2}

z_{\alpha/2} = z_{0.05/2}

z_{\alpha/2} = z_{0.025}

The z score is:

z_{\alpha/2} = z_{0.025} =1.96

The endpoints of the confidence level is:

(\bar x_1 - \bar x_2) \± z_{\alpha/2} * \sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}

2.0 \± 1.96 * \sqrt{\frac{2.1^2}{60}+\frac{3^2}{35}}

2.0 \± 1.96* \sqrt{\frac{4.41}{60}+\frac{9}{35}}

2.0 \± 1.96 * \sqrt{0.0735+0.2571}

2.0 \± 1.96* \sqrt{0.3306}

2.0 \± 1.1270

Split

(2.0 - 1.1270) \to (2.0 + 1.1270)

(0.8730) \to (2.1270)

Hence, the 95% confidence interval is:

CI = (0.8730,2.1270)

8 0
3 years ago
Select the correct answer.
katen-ka-za [31]

Answer:

3x - 4/2

Step-by-step explanation:

2 result(s) for "f(x) = 4x³ - 10 g(x)

6 0
2 years ago
In triangle ABC, angle A = 2x°, angle B = (x-45)° and angle C = (x-15)°.
Lelechka [254]
Sum\ of\ angles\ in\ triangle\ is\ equal\ to\ 180^{\circ}\\\\
To\ find\ x\ sum\ all\ angles:\\
2x+x-45+x-15=180\\\\
4x-60=180\ \ \ |Add\ 60\\\\
4x=60+180\\\\
4x=240\ \ \ |Divided\ by\ 4\\\\
x=60^{\circ}\\\\
\angle \  A=2x=2*60=120^{\circ}\\
\angle\ B=x-45=60-45=15^{\circ}\\
\angle\ C=x-15=60-15=45^{\circ}\\\\Triangle\ is\ \textbf{obtuse}.
5 0
3 years ago
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