The quarterback because he needs to be still for that split second while waiting for the ball to reach his hands, while everyone else is free to move when the ball moves
The kinetic energy of plane is 10285000 J
Kinetic energy is defined as the energy possed by an object in motion. The mathematical representation of kinetic energy is given below:
<h3>KE = ½mv²</h3>
Where:
KE is the kinetic energy
m is the mass of the object
v is the velocity of the object.
With the above formula, we can obtain kinetic energy of the plane as follow:
Mass (m) = 6800 kg
Velocity (v) = 55.0 m/s
<h3>Kinetic energy (KE) =? </h3>
KE = ½mv²
KE = ½ × 6800 × 55²
KE = 3400 × 3025
<h3>KE = 10285000 J</h3>
Therefore, the kinetic energy of plane is 10285000 J
Learn more: brainly.com/question/24713075
Assuming that they were at the exact distance away from you when they both turned on their lights your answer would be C. no matter how fast the person is moving light still travels at the same speed. please give brainliest
The space between them is shrinking at (60+40)= 100 mph. It started out being 120 miles. To shrink to zero will take
(120 miles) / (100 mph) = 1.2 hours
That's 1 hour and 12 minutes.
Answer:
Explanation:
Given that
The window height is 2m
And the window is 7.5m from the ground
Then the total height of the window from the ground is 7.5+2=9.5m
It takes the ball 0.32sec travelled pass the window.
When the ball get to the window, it has an initial velocity (u') and when it gets to the top of the window it has a final velocity ( v')
Now using the equation of free fall during this window travels
S=ut-½gt² against motion.
S=2, g=9.81, t=0.32sec
Then,
S=u't-½gt²
2=u'×0.32-½×9.81×0.32²
2=0.32u'-0.5023
2+0.5032=0.32u'
Then, 0.32u'=2.5032
u'=2.5032/0.32
u'=7.82m/s
This is the initial velocity as the ball got the the window
Now, let analyse from the window bottom to the ground which is a distance of 7.5m
Using the equation of free fall again
v²=u²-2gH
In this case the final velocity (v) is the velocity when the ball reach the bottom of the window i.e u'=7.82m/s,
While u is the original initial velocity from the throw of the ball
Then,
u'²=u²-2gH
7.82²=u²-2×9.81×7.5
61.146=u²-147.15
61.146+147.15=u²
Then, u²=208.296
So, u=√208.296
u=14.43m/s
The initial velocity of the ball form the throw is 14.43m/s
