What is the average velocity of a car that travels 450 km north in 9.0 hours?

Physics

1 answer:

Hatshy [7]3 years ago

3 0

The average velocity of a car that travels 450 km north in 9.0 h is 5.0 x 10 km/h

You might be interested in

Which statement correctly describes the classification of chemical reactions into different categories?(1 point) Not all reactio

VMariaS [17]

Answer:

its a

Explanation:

4 0

3 years ago

What waves are used in the hospitals to take pictures of bones

stich3 [128]

Answer:

An X-ray is used to take pictures of your bones. The waves that are used are known as radiation waves.

7 0

3 years ago

Frequency<br> In excercising

Gennadij [26K]

Frequency. This refers to how often you exercise. The point is to meet your goals without overtraining the body. When it comes to cardio: As a general rule of thumb, aim for a minimum of three cardio sessions per week.

3 0

3 years ago

Two identical asteroids travel side by side while touching one another. If the asteroids are composed of homogeneous pure iron a

victus00 [196]

Answer:

diameter = 21.81 ft

Explanation:

The gravitational force equation is:

$F=\frac{GMm}{R^{2} }$

Where:

F => Gravitational force or force of attraction between two masses
M => Mass of asteroid 1
m => Mass of asteroid 2
R => Distance between asteroids 1 and 2 (from center of gravity)

We also know that the asteroids are identical so their masses are identical:

Since R is the distance between centers of the two asteroids and their diameters are identical (see attachment), we can conclude that:

R=d=2r

We don´t know the mass of the asteroids but we know they are composed of pure iron, so we can relate their masses to their density:

m=ρV

This is going to be helpful because the volume of a sphere is:

$\frac{4}{3}\pi r^{3}$

And know we can write our original force of gravity equation in terms of the radius of the asteroids:

$F=\frac{GMm}{R^{2} } =\frac{Gmm}{(2r)^{2} } =\frac{Gm^{2} }{4r^{2} }$
$F=\frac{G ( \frac{4}{3}\pi r^{3}ρ)^{2} }{4r^{2} }$
$F= \frac{G(16)\pi ^{2} r^{6} ρ^{2}}{(9)(4)r^{2} } =\frac{G(16)\pi ^{2} r^{4}ρ^{2} }{36}$