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stiks02 [169]
3 years ago
11

A jar of sweets contains 5 yellow sweets, 4 red sweets, 8 green sweets, 4 orange sweets and 3 white sweets. Ola chooses a sweet

at random. What is the probability that she will pick either a yellow or orange sweet?
Mathematics
1 answer:
Lorico [155]3 years ago
7 0

Answer:

Probability to pick yellow or orange sweet = 3 / 8

Step-by-step explanation:

Given:

Number of yellow sweet = 5

Number of red sweet = 4

Number of green sweet = 8

Number of orange sweet = 4

Number of white sweet = 3

Find:

Probability to pick yellow or orange sweet

Computation:

Total number of sweets = 24 sweets

Probability to pick yellow = 5 / 24

Probability to pick orange = 4 / 24

Probability to pick yellow or orange sweet = 5/24 + 4 / 24

Probability to pick yellow or orange sweet = 9 / 24

Probability to pick yellow or orange sweet = 3 / 8

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Answer:

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Step-by-step explanation:

First we can turn both mixed fractions into improper fractions and to do that we multiply the whole number by the denominator and that add that to the top number.  So for 3 4/5 we would multiply 3 and 5 and than add 4 getting us to 19/5 doing the same to 4 5/6 gets us to 29/6.  Now in order to add fractions we need to get a common denominator.  The least common multiple of 5 and 6 is 30 so we will multiply each fraction by whatever number will give us 30 in the denomiator.  for 19/5 that number is 6 so our new fraction is 114/30 and for 29/6 that number is 5 so our new number is 145/30.  Now we just add the numerators and simplify.  114/30+145/30=259/30

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