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tamaranim1 [39]
3 years ago
5

Can someone help me on this

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
5 0

its option 3 because is doesn't have even sides

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1Ox+6-8x=9x +12-8x-2
Goshia [24]

Answer:

X=4

Step-by-step explanation:

3 0
3 years ago
What is 9/11=?/22 need help with this problem
KengaRu [80]
When you solve proportions, you have to cross multiply.

       9       x
      ---  =  ---         Multiply each numerator by the opposite denominator.
      11      22

(9)(22) = 11x        Then, multiply.

     198 = 11x        Then, divide.

       18 = x

4 0
4 years ago
What is the 23rd term of the arithmetic sequence where a1 = 8 and a9 = 48?
joja [24]

Answer:

23rd term of the arithmetic sequence is 118.

Step-by-step explanation:

In this question we have been given first term a1 = 8 and 9th term a9 = 48

we have to find the 23rd term of this arithmetic sequence.

Since in an arithmetic sequence

T_{n}=a+(n-1)d

here a = first term

n = number of term

d = common difference

since 9th term a9 = 48

48 = 8 + (9-1)d

8d = 48 - 8 = 40

d = 40/8 = 5

Now T_{23}= a + (n-1)d

= 8 + (23 -1)5 = 8 + 22×5 = 8 + 110 = 118

Therefore 23rd term of the sequence is 118.

4 0
3 years ago
Based on the information in the diagram?
muminat

Answer:

We can not use ASA property of congruence.

Step-by-step explanation:

In ΔHML and ΔHMK,

HL ≅ HK [Given]

LM ≅ KM [Given]

HM ≅ HM [Reflexive property]

m∠L ≅ m∠K [Given]

ASA property of congruence,

Angle-Side-Angle property of congruence.

False

SSS property of congruence,

Side-Side-Side property of congruence,

True

SAS property of congruence,

Side-Included Angle-Side property of congruence,

True.

Therefore, we can not use ASA property of congruence.

6 0
3 years ago
two hundred tickets for the school play were sold. tickets cost $2 for students and $3 for adults. the total amount collected wa
Gre4nikov [31]
A system of equations is good for a problem like this.
Let x be the number of student tickets sold
Let y be the number of adult tickets sold
x + y = 200
2x + 3y = 490
x = 200 - y
2(200 - y) + 3y = 490
400 - 2y + 3y = 490
400 + y = 490
y = 90
The number of adult tickets sold was 90.
x + 90 = 200 --> x = 110
2x + 3(90) = 490 --> 2x + 270 = 490 --> 2x = 220 --> x = 110
The number student tickets sold was 110.
4 0
3 years ago
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