I'll go out on a limb and suppose you're given the matrix

and you're asked to find the determinant of

, where

and given that

.
There are two properties of the determinant that come into play here:
(1) Whenever a single row/column is scaled by a constant

, then the determinant of the matrix is scaled by that same constant;
(2) Adding/subtracting rows does not change the value of the determinant.
Taken together, we have that
answer:
-1
work:
y = mx+ b
so we can tell that the Y intercept is 1, so we can plug that in. ( + b is the y-intercept)
y = mx + 1
plug in some values to find the slope.
(-1, 2)
2 = -m + 1
- 1 - 1
1 = -1m
/-1 /-1
-1 = m
the slope is -1.
i hope this helps! :D
Answer:
y=4x+19
Step-by-step explanation:
y-y1=m(x-x1)
y-(-1)=4(x-(-5))
y+1=4(x+5)
y=4x+20-1
y=4x+19
What are the choices given
The final step to solve this would be to determine the principal square root of both sides of the equation.