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irga5000 [103]
2 years ago
9

100 mL of a 0.4 M solution

Chemistry
1 answer:
Nitella [24]2 years ago
7 0

Answer:

99.6

Explanation:

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Sulfuric acid dissolves in water as H2SO4 2 H+(aq) + SO2 -2(aq). Which of the following solutions of H2SO4 will conduct the most
AlexFokin [52]
I believe it's 2.0 m
6 0
3 years ago
Read 2 more answers
How many moles of ammonia can be formed from 4.0 mol H2
Bess [88]

Answer: 1. 2.7 moles  of ammonia are formed

2. 12.0 moles  of hydrogen are required

3. 2.0 moles of nitrogen are required

Explanation:

The balanced chemical equation is:

N_2+3H_2\rightarrow 2NH_3

According to stoichiometry:

3 moles of hydrogen form = 2 moles of ammonia

Thus 4.0 moles of hydrogen form =\frac{2}{3}\times 4.0=2.7moles of ammonia

According to stoichiometry:

2 moles of ammonia are formed by = 3 moles of hydrogen

Thus 8.0 moles of ammonia are formed by  =\frac{3}{2}\times 8.0=12.0moles of hydrogen

According to stoichiometry:

3 moles of hydrogen react with = 1 mole of nitrogen

Thus 6.0 moles of hydrogen react with =\frac{1}{3}\times 6.0=2.0moles of nitrogen

3 0
2 years ago
Which mechanisms is most significant in returning the ion concentrations to the resting state?
IceJOKER [234]

Answer:

Active transport by the Na+-K+ pump

Explanation:

Active transport by the Na+-K+ pump

Maintenance (and restoration) of the resting ion concentrations depends on the Na+-K+ pump. Once gated ion channels are closed, the combined action of the pump and ion leakage (particularly that of K+) establishes a resting membrane potential in a typical neuron of around âˆ'70 mV.

5 0
2 years ago
For the reaction
iVinArrow [24]

Answer:

16 mol NaCl.

Explanation:

Do the train track method to cancel out all the units except moles of NaCl on top. Remember one mole of any gas occupies 22.4 L at STP.

179.2 L CO2  x 1 mol CO2/22.4 L CO2 x 2 mol NaCl/1 mol CO2

= 16 mol NaCl

5 0
2 years ago
What is the mass of silver in 4.3g AgNO3?
gregori [183]
4.22 grams.
1. First find out how much AgNO3 weighs with one mole (107.87 g Ag + 14.007 g N + 48 g O = 169.89 grams)
2. Find the percent of Ag you have. So, (107.87 g/mol Ag)/(169.89 g/mol AgNO3)= 0.63 * 100 = 63%.
3. If you have 6.7 grams total, you know 63% of it is going to be silver, so just multiply 6.7 grams by .63 and you get 4.22 g Ag
5 0
2 years ago
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