Why did the rice move as it did when the water was heated

In the reaction between phosphoric acid and ammonia, a compound forms containing 28.2 grams nitrogen, 8.1 grams hydrogen, 20.8 g

Mama L [17]

It would be 42.9 grams

5 0

3 years ago

Witch element is the number 14 on the periodic table

Pavlova-9 [17]

Answer:Silicon

Explanation:

Silicon - Element information, properties and uses | Periodic Table.

Royal Society of Chemistry › 14 › si...

Silicon - Element information, properties and uses | Periodic Table

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3 0

4 years ago

Which best describes why a liquid needs a container when a solid does not?Solids fill their containers, and liquids have definit

Rina8888 [55]

The correct answer choice which best describes why a liquid needs a container when a solid does not is simply because:

Solids have definite shapes, and liquids fill their containers.

Matter is classified as element, compounds and mixtures

<h3>What is an element?</h3>

An element is a substance which cannot be split into simpler forms by an ordinary chemical process. This simply goes to say that elements are substances which cannot be decomposed into simpler substances by ordinary chemical reactions.

An atom is the smallest unit or part of an element which can take part in a chemical reaction.

On a general note, elements are classified as thus:

Metals, non-metal, and metalloid.

The extreme left side elements in the periodic table are metals, for example, aluminum, sodium, calcium, caesium, etc.

However, elements on the right side are generally referred to as non-metals, carbon, chlorine, oxygen,

So therefore, the correct answer choice which best describes why a liquid needs a container when a solid does not is simply because:

Solids have definite shapes, and liquids fill their containers.

Learn more about atoms and elements:

brainly.com/question/6258301

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5 0

2 years ago

IV.2. The following problem considers the combustion of butane in a torch. Molecular weight of butane 58.0 g/mol. 2C4H10 + 1302

Anarel [89]

Answer:

(a) Oxygen

(b) 0.84 g

(c) 2.54 g

Explanation:

(a)

Explanation:

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Given: For butane

Given mass = 1.00 g

Molar mass of butane = 58.0 g/mol

Moles of butane = 1.00 g / 58.0 g/mol = 0.0172 moles

Given: For $O_2$

Given mass = 3.00 g

Molar mass of $O_2$ = 32.0 g/mol

Moles of $O_2$ = 3.00 g / 32.0 g/mol = 0.09375 moles

According to the given reaction:

$2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O$

2 moles of butane react with 13 moles of $O_2$

1 mole of butane react with 13/2 moles of $O_2$

0.0172 moles of butane react with (13/2)*0.0172 moles of $O_2$

Moles of $O_2$ required = 0.1118 moles

Available moles of $CuSO_4$ = 0.09375 moles

<u>Limiting reagent is the one which is present in small amount. Thus, $O_2$ is limiting reagent. (0.09375 < 0.1118 )</u>

(b)

The formation of the product is governed by the limiting reagent. So,

13 moles of $O_2$ react with 2 moles of butane

1 mole of $O_2$ react with 2/13 moles of butane

0.09375 mole of $O_2$ react with (2/13)*0.09375 moles of butane

Moles of butane used = 0.0144 moles

Molar mass of butane = 58.0 g/mol

<u>Mass of butane used = Moles × Molar mass = 0.0144 × 58.0 g = 0.84 g</u>

(c)

13 moles of $O_2$ on reaction forms 8 moles of carbon dioxide

1 mole of $O_2$ on reaction forms 8/13 moles of carbon dioxide

0.09375 mole of $O_2$ on reaction forms (8/13)*0.09375 moles of carbon dioxide

Moles of carbon dioxide obtained = 0.05769 moles

Molar mass of $CO_2$ = 44.0 g/mol

<u>Mass of $CO_2$ = Moles × Molar mass = 0.05769 × 44.0 g = 2.54 g</u>

6 0

3 years ago

Measurements show that unknown compound X has the following composition:

zvonat [6]

Answer: The empirical formula of X is $C_{5}H_4O_2$ .

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 62.4 g

Mass of H = 4.19 g

Mass of O = 33.2 g

Step 1 : convert given masses into moles.

Moles of C= $\frac{\text{ given mass of Na}}{\text{ molar mass of Na}}= \frac{62.4g}{12g/mole}=5.2moles$

Moles of H= $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{4.19g}{1g/mole}=4.19moles$

Moles of O = $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{33.2g}{16g/mole}=2.1moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{5.2}{2.1}=2.5$

For H = $\frac{4.19}{2.1}=2$

For O = $\frac{2.1}{2.1}=1$

The ratio of C: H: O = 2.5 : 2 : 1

Converting it into simple whole number ratios by multiplying by 2:

Hence the empirical formula of X is $C_{5}H_4O_2$ .

6 0

3 years ago