Answer:
a. ΔΗ > 0, solution feels cold
Explanation:
Hello,
In this case, endothermic process are those in which we can find that the products have more energy than the reactants, therefore energy is absorbed, for which the following equation:
Must be greater than 0 (positive) thereby, for a solution process we find that the solution feels cold, in such a way, answer is a. ΔΗ > 0, solution feels cold.
Regards.
Answer:
Stoichiometry measures these quantitative relationships, and is used to determine the amount of products and reactants that are produced or needed in a given reaction. Describing the quantitative relationships among substances as they participate in chemical reactions is known as reaction stoichiometry.
Explanation:
<span>ZnS + O --> ZnO + SO
Okay so first you have to count up the number of elements on each side of the equation. Your objective is to have the same number of each element on both sides.
Left Side:
Zn - 1
S - 1
O - 1
Right Side:
Zn - 1
S - 1
O - 2
Since there are two oxygens on the right side, you have to add a coefficient of 2 to the oxygen on the left side. The coefficient tells us that that element or molecule is being multiplied by the value of coefficient. Since we're adding a coefficient of 2 to the oxygen on the left side, there are now 2 oxygens on that side. Because that is the same amount of oxygen as on the right, the equation is now balanced.
Your final equation should look like this: </span>ZnS + 2O --> ZnO + SO
In conclusion, the answer is 2.
Answer:
7.41 × 10⁻⁵
Explanation:
Let's consider the basic dissociation reaction of trimethylamine (CH₃)N).
(CH₃)N + H₂O = (CH₃)NH⁺ + OH⁻
According to Brönsted-Lowry, in this reaction (CH₃)N is a base and (CH₃)NH⁺ is its conjugate acid. The pKb for (CH₃)N is 9.87. We can calculate the pKa of (CH₃)NH⁺ using the following expression.
pKa + pKb = 14
pKa = 14 - pKb = 14 - 9.87 = 4.13
Then, we can calculate the acid dissociation constant for (CH₃)NH⁺ using the following expression.
pKa = -log Ka
Ka = antilog - pKa = antilog -4.13 = 7.41 × 10⁻⁵
