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Lorico [155]
3 years ago
13

A student was asked to find the density of an unknown object. The student found that the mass of the object was 35.49 g. The stu

dent used water displacement to find the volume of the object. The graduated cylinder originally contained 45.1 mL of water. After the object was placed in the graduated cylinder, the volume was 52.3 mL. What is the density of the unknown object? Remember to round your answer to the correct number of significant figures and include the correct units. (Note: 1 mL = 1 cm3)
Chemistry
1 answer:
marusya05 [52]3 years ago
8 0

Answer:

4.29 /mL

Explanation:

density= mass/volume

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5 0
2 years ago
In a normal cellular protein, where would you expect to find a hydrophobic amino acid like valine?
Irina-Kira [14]
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5 0
3 years ago
Considering the volumes and the concentrations used in mixture 1, what percentage of the moles of H2O2 present have been consume
Kisachek [45]

Answer:

1 mol of H2O2 consumes 1 mol of S2O32, then 0.0005 mol of I- reacts with 0.00025 moles of H2O2

Thus, initial moles of H2O2 present in the mix is equal to 0.0102 moles.

Amount of moles of H2O2 that reacts with I- is equal to 0.00025 moles.

The amount of I ions that is oxidized by H2O2 and the iodine, I2 that is produced, is consumed by the S2O32- ions and are transformed into I ions. The amount of I ions that are consumed by H2O2 is equal to the amount of ion that is produced by S2O32-.

Explanation:

the total volume of the mixture is equal to:

Vmix = 75 + 30 + 25 + 5 + 5 + 10 = 150 mL

the moles of each species in the mix equals:

Na2S2O3 = 0.05 * 0.005 = 0.00025 moles

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H2O2 = 1.02 * 0.01 = 0.0102 moles

the following equation shows the reaction between I2 and S2O32:

I2 + S2O32 = 2I- + S4O62-

The same way:

2I- + 2H+ + H2O2 = I2 + 2H2O

1 mol of H2O2 consumes 1 mol of S2O32, then 0.0005 mol of I- reacts with 0.00025 moles of H2O2

Thus, initial moles of H2O2 present in the mix is equal to 0.0102 moles.

Amount of moles of H2O2 that reacts with I- is equal to 0.00025 moles.

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3 0
3 years ago
A gas occupies 1.00cm^3 at STP. What volume does it occupy at 710.0 mm Hg and 55.0°C
Lera25 [3.4K]

Answer:

Final volume is 1.29cm³

Explanation:

Using combined gas law:

P₁V₁/T₁ = P₂V₂/T₂

<em>Where P is pressure, V volume and T absolute temperature of 1, initial state and 2, final state of a gas.</em>

<em />

We can solve the volume of the gas:

P₁ = 1atm at STP

V₁ = 1cm³

T₁ = 273.15K at STP

P₂ = 710mmHg * (1atm / 760mmHg) = 0.9342atm

V₂ = ?

T₂ = 55.0°C + 273.15K = 328.15K

Replacing:

1atm*1cm³/273.15K = 0.9342atm*V₂/328.15K

1.29cm³ = V₂

<h3>Final volume is 1.29cm³</h3>

<em />

6 0
3 years ago
Why do cells prefer to use carbohydrates as a source of energy before they use fats and proteins.
Semmy [17]

The primary role of carbohydrates is to supply energy to all cells in the body. Many cells prefer glucose as a source of energy versus other compounds like fatty acids. Because the energy from glucose comes from the chemical bonds between the carbon atoms.

7 0
3 years ago
Read 2 more answers
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