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3 years ago

Pls I’ll literally give brainliest to whoever

Mathematics

1 answer:

rjkz [21]3 years ago

3 0

D the bottom answer, A= 15.53 P= 20.42

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3. A large fruit dish with a 36 in. diameter is placed in the center of a banquet across and is completely filled with apples. T

Serga [27]

Answer:

a) 11%

b) 56%

Step-by-step explanation:

a) A= πr^2 6^2π= 36π A= 18^2π = 324π

36π/324π = .111111111111111111111111 or 11%

remember to cancel out the pi symbols when you are showing your work

(put a line across the pi symbols when dividing)

b) A= πr^2 18^2 π = 324π

A= πr^2 12^2π = 144π

324 – 144 = 180

180π/324π = .5555555555555555555555556 or 56%

remember to cancel out the pi symbols when you are showing your work

(put a line across the pi symbols when dividing)

3 0

3 years ago

1. To the nearest tenth of a centimeter, how tall is a

Setler [38]

It’s A because when u do (6.4)^2 times pi equals 128.6796351 and u subtract to the total volume(1119.5cm) and equals to 8.69; u later round to nearest tenth which equals to A, 8.7cm

4 0

3 years ago

A rate that compares quantity to 100 is called a ________.

PIT_PIT [208]

it is called a percent.

8 0

3 years ago

Read 2 more answers

The two largest lizards in the united states are the gila monster and the chuckwalla. The average gila monster is 0.608 meter lo

Mamont248 [21]

Answer:

Gila Monster is 1.54 times that of Chuckwalla.

Step-by-step explanation:

Given:

Average Length of Gila Monster = 0.608 m

Average Length of Chuckwalla = 0.395 m

We need to find the number of times the Gila monster is as the Chuckwalla.

Solution:

Now we know that;

To find the number of times the Gila monster is as the Chuckwalla we will divide the Average Length of Gila Monster by Average Length of Chuckwalla.

framing in equation form we get;

number of times the Gila monster is as the Chuckwalla = $\frac{0.608}{0.395} = 1.5392$

Rounding to nearest hundredth's we get;

number of times the Gila monster is as the Chuckwalla = 1.54

Hence Gila Monster is 1.54 times that of Chuckwalla.

5 0

3 years ago

Given right triangle ABC with altitude BD drawn to hypotenuse AC. If AC = 20 and DC = 5, what is the length of BC? (Note: the fi

11111nata11111 [884]

Answer:

21.2 or 15 sqrt of 2 (PETHAGOREOM theorem)

Step-by-step explanation:

a^2+b^2=c^2

20^2+5^2=C^2

400+25=C^2

450=C^2

sqrt 450=

15 sqrt of 2 or 21.2

4 0

3 years ago