F(x) = x+4
f(4) = 8, f(5) = 9
Change = 1
f(x) = 3x-7
f(-3) = -16, f(5) = 8
Change = 24/8 = 3
f(x) = 9x+1
f(-5) = -44, f(-2) = -17
Change = 27/3 = 9
f(x) = 2x+9
f(1) = 11, f(2) = 13
Change = 2
In order: f(x) = 9x+1, f(x) = 3x-7, f(x) = 2x+9, f(x) = x+4
Answer:
2m^4 - 11m³ + m + 8
Step-by-step explanation:
(2m - 5m³) - (5m + 3m³ - 7m^4) + (8 - 3m³ - 5m^4 + 4m)
2m - 5m³ - 5m - 3m³ + 7m^4 + 8 - 3m³ - 5m^4 + 4m
7m^4 - 5m^4 - 5m³ - 3m³ - 3m³ + 2m - 5m + 4m + 8
2m^4 - 11m³ + m + 8
The probability that the person pulls 1 blue M&M given that one is only allowed to pull 5 random M&M's per day will be 0.6450.
<h3>How to calculate probability?</h3>
From the information given, there are 1,023 M&M's in a bag and out of 1,023 M&M's, 132 M&M's are blue.
Therefore, the probability of getting a blue M&M will be:
= 132/1023
= 0.1290
Therefore, since the person is given the chance to pull 5 random M&M's per day, the probability will be:
= 0.1290 × 5
= 0.6450
Learn more about probability on:
brainly.com/question/24756209
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To find the mean all you have to do is add all the numbers...
you should get -30
and divide by a number of numbers, there are 6
so -30/6 is -5
Solving for y right?
2y = 3x + 4 - x
2y = 2x + 4
y = 2x + 4 over 2
y = 2 (x + 2) over 2
y = x + 2
y - 3 = 2x - 6 over 2
y - 3 = 2(x - 3) over 2
y - 3 = x - 3
y = x
x - y - 2 = 2(2x + 1)
-y - 2 = 2(2x + 1) - x
-y = 2(2x + 1) - x + 2
y = -2(2x + 1) + x - 2
